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A custom printing company charges a one-time setup fee of $28 for each printing job. In addition to the setup...

GMAT Algebra : (Alg) Questions

Source: Prism
Algebra
Linear inequalities in 1 or 2 variables
MEDIUM
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Notes
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A custom printing company charges a one-time setup fee of \(\$28\) for each printing job. In addition to the setup fee, the company charges \(\$12.75\) for each item printed. If a customer has a budget of \(\$340\), what is the maximum number of items that can be printed without exceeding the budget?

Enter your answer as an integer.

Enter your answer here
Solution

1. TRANSLATE the problem information

  • Given information:
    • Setup fee: $28 (one-time charge)
    • Cost per item: $12.75
    • Budget limit: $340
    • Need: Maximum number of items without exceeding budget
  • What this tells us: We need an inequality since we cannot exceed the budget.

2. TRANSLATE to set up the mathematical relationship

  • Let \(\mathrm{x}\) = number of items to be printed
  • Total cost = Setup fee + (Cost per item × Number of items)
  • Total cost = \(\mathrm{28 + 12.75x}\)
  • Constraint: Total cost ≤ Budget
  • Mathematical inequality: \(\mathrm{28 + 12.75x \leq 340}\)

3. SIMPLIFY by solving the inequality

  • Subtract the setup fee from both sides:
    \(\mathrm{12.75x \leq 340 - 28}\)
    \(\mathrm{12.75x \leq 312}\)
  • Divide both sides by 12.75 (use calculator):
    \(\mathrm{x \leq 312 \div 12.75}\)
    \(\mathrm{x \leq 24.47...}\)

4. APPLY CONSTRAINTS to find the final answer

  • Since you can't print a partial item, the number of items must be a whole number
  • We must round DOWN to 24 (not up to 25, as that would exceed the budget)
  • Verification: \(\mathrm{28 + 12.75(24) = 28 + 306 = \$334 \leq \$340}\)

Answer: 24




Why Students Usually Falter on This Problem

Most Common Error Path:

Weak APPLY CONSTRAINTS reasoning: Students correctly solve to get \(\mathrm{x \leq 24.47...}\) but then round UP to 25 instead of down to 24.

They think "24.47 is closer to 25, so I should round to 25." However, this violates the budget constraint since \(\mathrm{28 + 12.75(25) = \$346.75}\), which exceeds the $340 budget. This leads to an incorrect answer of 25.

Second Most Common Error:

Incomplete TRANSLATE execution: Students forget to include the setup fee and only focus on the per-item cost.

They set up \(\mathrm{12.75x \leq 340}\), which gives \(\mathrm{x \leq 26.67...}\), leading them to answer 26. This completely ignores the $28 setup fee that must be paid regardless of how many items are printed.

The Bottom Line:

This problem tests whether students understand that real-world constraints require careful attention to inequality direction and realistic rounding. The mathematical solution gives a decimal, but the real-world context demands a whole number that doesn't violate the budget limit.

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