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The table gives the distribution of votes for a new school mascot and grade level for students.MascotSixthSeventhEighthTotalBadger49922Lion92920Longho...

GMAT Problem-Solving and Data Analysis : (PS_DA) Questions

Source: Practice Test
Problem-Solving and Data Analysis
Probability and conditional probability
EASY
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Notes
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The table gives the distribution of votes for a new school mascot and grade level for students.

MascotSixthSeventhEighthTotal
Badger49922
Lion92920
Longhorn46414
Tiger69924
Total23263180

If one of these students is selected at random, what is the probability of selecting a student whose vote for new mascot was for a lion?

A
\(\frac{1}{9}\)
B
\(\frac{1}{6}\)
C
\(\frac{1}{4}\)
D
\(\frac{2}{3}\)
Solution

1. TRANSLATE the probability question

  • The question asks: "What is the probability of selecting a student whose vote was for a lion?"
  • This translates to: \(\mathrm{P(lion\ voter)} = \frac{\mathrm{Number\ of\ students\ who\ voted\ for\ lion}}{\mathrm{Total\ number\ of\ students}}\)

2. VISUALIZE the table to find lion votes

  • Look at the "Lion" row in the table
  • Add across all grade levels: \(9 + 2 + 9 = 20\) students voted for lion
  • The total number of students is shown in the bottom right: 80 students

3. INFER the probability calculation

  • We now have: \(\mathrm{P(lion\ voter)} = \frac{20}{80}\)
  • This fraction needs to be simplified to match the answer choices

4. SIMPLIFY the fraction

  • \(\frac{20}{80} = \frac{1}{4}\) (dividing both numerator and denominator by 20)

Answer: C. \(\frac{1}{4}\)




Why Students Usually Falter on This Problem

Most Common Error Path:

Weak TRANSLATE skill: Students misunderstand what the question is asking and calculate the wrong probability.

Instead of finding \(\mathrm{P(lion\ voter)}\), they might calculate:

  • \(\mathrm{P(lion\ voter\ |\ specific\ grade)}\) using just one grade level
  • \(\mathrm{P(specific\ grade\ |\ lion\ voter)}\) reversing the conditional probability

This leads to incorrect calculations like \(\frac{9}{23}\) or \(\frac{2}{26}\) from individual grade columns, which don't match any answer choices. This causes them to get stuck and randomly select an answer.

Second Most Common Error:

Poor VISUALIZE execution: Students misread the table and use incorrect numbers.

Common mistakes include:

  • Using 22 (total for Badger) instead of 20 for lion votes
  • Using row totals instead of the specific lion data
  • Confusing rows and columns when reading the table

This may lead them to select Choice A (\(\frac{1}{9}\)) if they incorrectly use \(\frac{9}{80}\) from just one grade level.

The Bottom Line:

This problem tests whether students can correctly interpret what probability is being asked for and accurately extract information from a two-way table. The key insight is recognizing that "selecting a student who voted for lion" means finding what fraction of all 80 students voted for lion, regardless of their grade level.

Answer Choices Explained
A
\(\frac{1}{9}\)
B
\(\frac{1}{6}\)
C
\(\frac{1}{4}\)
D
\(\frac{2}{3}\)
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