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A right pyramid has a square base. The side length of the square base is 13/3 meters, and the height...

GMAT Geometry & Trigonometry : (Geo_Trig) Questions

Source: Prism
Geometry & Trigonometry
Area and volume formulas
MEDIUM
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A right pyramid has a square base. The side length of the square base is \(\frac{13}{3}\) meters, and the height of the pyramid is \(\frac{7}{2}\) meters. What is the volume, in cubic meters, of the pyramid?

A

\(\frac{1183}{36}\)

B

\(\frac{1183}{54}\)

C

\(\frac{1183}{27}\)

D

\(\frac{1183}{18}\)

Solution

1. TRANSLATE the problem information

  • Given information:
    • Right pyramid with square base
    • Side length of square base: \(\frac{13}{3}\) meters
    • Height of pyramid: \(\frac{7}{2}\) meters
    • Need to find: Volume in cubic meters
  • What this tells us: We have all the measurements needed to apply the pyramid volume formula.

2. INFER the approach

  • Since we have a pyramid, we'll use: \(\mathrm{V} = \frac{1}{3} \times \mathrm{Base\:Area} \times \mathrm{Height}\)
  • First we need the base area, then substitute everything into the volume formula
  • The base is square, so we'll need to square the side length

3. Calculate the base area

  • Base Area = \(\left(\mathrm{side\:length}\right)^2 = \left(\frac{13}{3}\right)^2\)
  • Base Area = \(\frac{169}{9}\) square meters

4. SIMPLIFY by applying the volume formula

  • \(\mathrm{V} = \frac{1}{3} \times \frac{169}{9} \times \frac{7}{2}\)
  • Multiply the numerators: \(1 \times 169 \times 7 = 1183\)
  • Multiply the denominators: \(3 \times 9 \times 2 = 54\)
  • \(\mathrm{V} = \frac{1183}{54}\) cubic meters

Answer: B. \(\frac{1183}{54}\)




Why Students Usually Falter on This Problem


Most Common Error Path:

Weak SIMPLIFY execution: Students make arithmetic errors when multiplying the fractions, particularly when calculating \(1 \times 169 \times 7 = 1183\) or \(3 \times 9 \times 2 = 54\). Common mistakes include getting 1173 instead of 1183 in the numerator, or miscalculating the denominator as 36 or 27.

This may lead them to select Choice A (\(\frac{1183}{36}\)) or Choice C (\(\frac{1183}{27}\)).


Second Most Common Error:

Missing conceptual knowledge about pyramid volume: Students might confuse the pyramid volume formula with other volume formulas, forgetting the \(\frac{1}{3}\) factor and just multiplying Base Area × Height directly.

This leads to getting \(\frac{1183}{18}\) and selecting Choice D.


The Bottom Line:

This problem tests careful fraction arithmetic more than complex geometric reasoning. The key is systematically working through the multiplication without rushing the calculations.

Answer Choices Explained
A

\(\frac{1183}{36}\)

B

\(\frac{1183}{54}\)

C

\(\frac{1183}{27}\)

D

\(\frac{1183}{18}\)

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