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Question:The graph of a quadratic function g is a parabola in the xy-plane with vertex \((\mathrm{h},\mathrm{k})\). Given that h =...

GMAT Advanced Math : (Adv_Math) Questions

Source: Prism
Advanced Math
Nonlinear functions
MEDIUM
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Question:

The graph of a quadratic function g is a parabola in the xy-plane with vertex \((\mathrm{h},\mathrm{k})\). Given that \(\mathrm{h = -3}\), which of the following equations, all of which define g for all values of x, shows the value of k as a constant term or coefficient?

A
\(\mathrm{g(x) = -x^2 - 6x - 2}\)
B
\(\mathrm{g(x) = -x(x+6) - 2}\)
C
\(\mathrm{g(x) = -(x+1)(x+5) + 3}\)
D
\(\mathrm{g(x) = -(x+3)^2 + 7}\)
Solution

1. TRANSLATE the problem requirements

  • Given information:
    • Vertex is at \((h,k)\) where \(h = -3\)
    • Need to find which form shows \(k\) as a constant term or coefficient
  • What this means: I need to identify which algebraic form explicitly displays the y-coordinate of the vertex (k value) without requiring any calculations.

2. INFER which form explicitly shows k

  • The vertex form of a parabola is \(\mathrm{g(x)} = \mathrm{a(x-h)}^2 + \mathrm{k}\)
  • With \(\mathrm{h} = -3\), this becomes \(\mathrm{g(x)} = \mathrm{a(x+3)}^2 + \mathrm{k}\)
  • In vertex form, \(\mathrm{k}\) appears directly as the constant term added to the squared expression

3. INFER why other forms don't show k directly

  • Standard form: \(\mathrm{g(x)} = \mathrm{ax}^2 + \mathrm{bx} + \mathrm{c}\) shows the y-intercept \((\mathrm{c})\), not the vertex y-coordinate
  • Factored forms: require expanding or other calculations to find the vertex
  • Only vertex form displays \(\mathrm{k}\) immediately without any work

4. Examine each choice

Looking for the pattern \(\mathrm{g(x)} = \mathrm{a(x+3)}^2 + \mathrm{k}\):

  1. \(\mathrm{g(x)} = -\mathrm{x}^2 - 6\mathrm{x} - 2\) → Standard form (hides k)
  2. \(\mathrm{g(x)} = -\mathrm{x(x+6)} - 2\) → Partially factored (hides k)
  3. \(\mathrm{g(x)} = -(\mathrm{x}+1)(\mathrm{x}+5) + 3\) → Factored form (hides k)
  4. \(\mathrm{g(x)} = -(\mathrm{x}+3)^2 + 7\) → Vertex form (shows \(\mathrm{k} = 7\) explicitly)

Answer: D




Why Students Usually Falter on This Problem

Most Common Error Path:

Weak INFER skill: Students see constant terms in multiple answer choices (like -2 in choices A and B, or +3 in choice C) and incorrectly assume these represent k.

They don't understand that k specifically refers to the y-coordinate of the vertex, which only appears explicitly in vertex form. They might think "any constant term shows k" rather than recognizing that k has a specific mathematical meaning tied to the vertex location.

This may lead them to select Choice A (-2) or Choice C (+3) based on seeing obvious constant terms.


Second Most Common Error:

Poor TRANSLATE reasoning: Students misunderstand what "shows the value of k as a constant term" means, thinking it just means "contains a constant number somewhere."

They fail to connect this requirement to the vertex form structure, not realizing that the question is asking which form makes k immediately visible without any calculation or conversion work.

This leads to confusion and guessing among the choices that contain constants.


The Bottom Line:

This problem tests whether students understand that different algebraic forms of the same quadratic function reveal different information directly. Only vertex form makes the vertex coordinates immediately visible.

Answer Choices Explained
A
\(\mathrm{g(x) = -x^2 - 6x - 2}\)
B
\(\mathrm{g(x) = -x(x+6) - 2}\)
C
\(\mathrm{g(x) = -(x+1)(x+5) + 3}\)
D
\(\mathrm{g(x) = -(x+3)^2 + 7}\)
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