A laboratory begins an experiment with 400.0 grams of a radioactive isotope. The isotope decays exponentially, and no additional material...
GMAT Advanced Math : (Adv_Math) Questions
A laboratory begins an experiment with 400.0 grams of a radioactive isotope. The isotope decays exponentially, and no additional material is added or removed during the experiment. The mass of the isotope is given by an exponential function M, where \(\mathrm{M(t)}\) is the mass in grams \(\mathrm{t}\) hours after the experiment begins. After 10 hours, the mass of the isotope is 43.0 grams. Which equation could define M?
- \(\mathrm{M(t) = 400.0(0.8)^t}\)
- \(\mathrm{M(t) = 400.0(0.2)^t}\)
- \(\mathrm{M(t) = 357.0(0.8)^t}\)
- \(\mathrm{M(t) = 43.0(0.8)^t}\)
- \(\mathrm{M(t) = 400.0(1.2)^t}\)
1. TRANSLATE the problem information
- Given information:
- Initial mass at \(\mathrm{t = 0}\): 400.0 grams
- Mass at \(\mathrm{t = 10}\) hours: 43.0 grams
- Need exponential decay function \(\mathrm{M(t)}\)
- This tells us we need the form \(\mathrm{M(t) = P \times (decay\ factor)^t}\) where \(\mathrm{P = 400.0}\)
2. INFER the approach
- Since we know two points on the exponential curve, we can find the decay factor
- The condition \(\mathrm{M(10) = 43.0}\) will let us solve for the unknown decay factor
- Once we have the decay factor, we can write the complete function
3. Set up the equation using the given condition
From \(\mathrm{M(t) = 400.0 \times (decay\ factor)^t}\) and \(\mathrm{M(10) = 43.0}\):
\(\mathrm{400.0 \times (decay\ factor)^{10} = 43.0}\)
4. SIMPLIFY to find the decay factor
- Divide both sides by 400.0:
\(\mathrm{(decay\ factor)^{10} = \frac{43.0}{400.0} = 0.1075}\)
- Take the 10th root of both sides (use calculator):
\(\mathrm{decay\ factor = (0.1075)^{\frac{1}{10}} \approx 0.7984 \approx 0.8}\)
5. Write the complete function and verify
- The function is: \(\mathrm{M(t) = 400.0 \times (0.8)^t}\)
- SIMPLIFY to verify:
\(\mathrm{M(10) = 400.0 \times (0.8)^{10}}\)
\(\mathrm{= 400.0 \times (0.1073741824)}\)
\(\mathrm{\approx 43.0}\) ✓
Answer: A
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak INFER skill: Students don't recognize that they need to use the condition \(\mathrm{M(10) = 43.0}\) to find the specific decay factor. Instead, they try to guess which answer "looks right" based on the initial value of 400.0.
They might notice that choices A, B, and E all start with 400.0 (which is correct for the initial amount), but then randomly pick between the decay factors 0.8, 0.2, or 1.2 without doing the calculation. Since \(\mathrm{1.2 \gt 1}\) represents growth (not decay), they might eliminate E, but still guess between A and B.
This may lead them to select Choice B (\(\mathrm{M(t) = 400.0 \times (0.2)^t}\)) or causes confusion and guessing.
Second Most Common Error:
Poor TRANSLATE reasoning: Students misunderstand what the initial amount should be in the exponential function. They might think the function should start with the remaining amount (43.0) or the amount that decayed (\(\mathrm{357.0 = 400.0 - 43.0}\)).
This leads them to consider choices C or D, not realizing that the exponential decay model always starts with the original amount at \(\mathrm{t = 0}\).
This may lead them to select Choice C (\(\mathrm{M(t) = 357.0 \times (0.8)^t}\)) or Choice D (\(\mathrm{M(t) = 43.0 \times (0.8)^t}\)).
The Bottom Line:
Success requires both understanding the structure of exponential decay functions AND using the given data point to determine the specific decay factor through algebraic manipulation.