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A random sample of 50 people from a town with a population of 14,878 were asked to name their favorite...

GMAT Problem-Solving and Data Analysis : (PS_DA) Questions

Source: Official
Problem-Solving and Data Analysis
Inference from sample statistics and margin of error
EASY
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Notes
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A random sample of 50 people from a town with a population of 14,878 were asked to name their favorite flavor of ice cream. If 7 people in the sample named chocolate as their favorite ice-cream flavor, about how many people in the town would be expected to name chocolate?

A

350

B

2,100

C

7,500

D

10,500

Solution

1. TRANSLATE the problem information

  • Given information:
    • Sample size: 50 people
    • Chocolate lovers in sample: 7 people
    • Total town population: 14,878 people
    • Need to find: Expected chocolate lovers in entire town

2. INFER the mathematical approach

  • Key insight: Since this was a random sample, the proportion of chocolate lovers in the sample should be the same as in the entire population
  • This means we can set up a proportion: Sample ratio = Population ratio
  • Strategy: Set up the proportion and solve for the unknown

3. TRANSLATE into mathematical notation

  • Sample proportion: \(\frac{7}{50}\)
  • Population proportion: \(\frac{x}{14,878}\) (where x is what we're looking for)
  • Proportion equation: \(\frac{7}{50} = \frac{x}{14,878}\)

4. SIMPLIFY by solving the proportion

  • Cross multiply: \(7 \times 14,878 = 50 \times x\)
  • Calculate: \(104,146 = 50x\)
  • Divide both sides by 50: \(x = 104,146 \div 50\) (use calculator)
  • Result: \(x = 2,082.92\)

5. APPLY CONSTRAINTS to select final answer

  • Look at answer choices: A. 350, B. 2,100, C. 7,500, D. 10,500
  • Our calculated value 2,082.92 is closest to 2,100

Answer: B. 2,100




Why Students Usually Falter on This Problem


Most Common Error Path:

Weak INFER skill: Students don't recognize this as a proportion problem and instead try to use the sample data directly or perform incorrect calculations.

For example, they might multiply \(7 \times \frac{14,878}{50}\) incorrectly, or try to scale up by doing \(7 \times 14,878 = 104,146\), leading them to select Choice D (10,500) as the closest large number.


Second Most Common Error:

Poor TRANSLATE reasoning: Students set up the proportion incorrectly, perhaps writing it as \(\frac{50}{7} = \frac{14,878}{x}\) or mixing up which numbers go where.

This leads to incorrect cross multiplication like \(50 \times 14,878 = 7 \times x\), giving \(x = 106,271\), which doesn't match any answer choice and causes confusion and guessing.


The Bottom Line:

This problem requires recognizing that random sampling creates proportional relationships between sample and population. Students who miss this connection often resort to inappropriate arithmetic operations instead of systematic proportion solving.

Answer Choices Explained
A

350

B

2,100

C

7,500

D

10,500

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