Rectangle ABCD is similar to rectangle EFGH. The area of rectangle ABCD is 648 square inches, and the area of...
GMAT Geometry & Trigonometry : (Geo_Trig) Questions
Rectangle ABCD is similar to rectangle EFGH. The area of rectangle ABCD is \(648\) square inches, and the area of rectangle EFGH is \(72\) square inches. The length of the longest side of rectangle ABCD is \(36\) inches. What is the length, in inches, of the longest side of rectangle EFGH?
\(\mathrm{4}\)
\(\mathrm{9}\)
\(\mathrm{12}\)
\(\mathrm{36}\)
1. TRANSLATE the problem information
- Given information:
- Rectangle ABCD is similar to rectangle EFGH
- Area of ABCD = 648 square inches
- Area of EFGH = 72 square inches
- Longest side of ABCD = 36 inches
- Need to find: longest side of EFGH
2. INFER the key relationship
- Since the rectangles are similar, all corresponding sides are proportional by the same scale factor \(\mathrm{k}\)
- This means: if each side of EFGH is \(\mathrm{k}\) times the corresponding side of ABCD, then the area of EFGH is \(\mathrm{k^2}\) times the area of ABCD
- Why \(\mathrm{k^2}\)? Because area = length × width, so if both dimensions scale by \(\mathrm{k}\), area scales by \(\mathrm{k \times k = k^2}\)
3. TRANSLATE this relationship into an equation
- Area of EFGH = \(\mathrm{k^2}\) × Area of ABCD
- Substituting: \(\mathrm{72 = k^2 \times 648}\)
4. SIMPLIFY to find the scale factor
- \(\mathrm{k^2 = \frac{72}{648} = \frac{1}{9}}\)
- Take the square root: \(\mathrm{k = \sqrt{\frac{1}{9}} = \frac{1}{3}}\)
- This means each side of EFGH is \(\mathrm{\frac{1}{3}}\) the length of the corresponding side in ABCD
5. SIMPLIFY to find the longest side of EFGH
- Longest side of EFGH = \(\mathrm{k}\) × longest side of ABCD
- Longest side of EFGH = \(\mathrm{\frac{1}{3} \times 36 = 12}\) inches
Answer: C. 12
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak INFER skill: Students don't recognize that areas scale by \(\mathrm{k^2}\) when sides scale by \(\mathrm{k}\). Instead, they assume areas scale by the same factor as the sides.
They might think: "Area of EFGH is 72 and area of ABCD is 648, so EFGH is \(\mathrm{\frac{72}{648} = \frac{1}{9}}\) the size. Therefore, each side of EFGH is \(\mathrm{\frac{1}{9}}\) the length of the corresponding side in ABCD."
This leads them to calculate: \(\mathrm{36 \times \frac{1}{9} = 4}\) inches, causing them to select Choice A (4).
Second Most Common Error:
Poor TRANSLATE reasoning: Students correctly find \(\mathrm{k = \frac{1}{3}}\) but then get confused about which rectangle is larger and which scale factor to use.
They might calculate \(\mathrm{k^2 = \frac{72}{648} = \frac{1}{9}}\) correctly, but then think "ABCD is 9 times larger than EFGH in area" and incorrectly conclude the side ratio is \(\mathrm{9:1}\) instead of \(\mathrm{3:1}\). This leads them to select Choice B (9).
The Bottom Line:
The key insight that trips up most students is understanding that when similar figures have sides that differ by factor \(\mathrm{k}\), their areas differ by factor \(\mathrm{k^2}\). Missing this fundamental relationship about area scaling makes the entire problem unsolvable using the correct approach.
\(\mathrm{4}\)
\(\mathrm{9}\)
\(\mathrm{12}\)
\(\mathrm{36}\)