A rectangle has length x and width y, where both dimensions are positive. The area of the rectangle is 18...
GMAT Advanced Math : (Adv_Math) Questions
A rectangle has length \(\mathrm{x}\) and width \(\mathrm{y}\), where both dimensions are positive. The area of the rectangle is \(\mathrm{18}\) square units. The perimeter of the rectangle is \(\mathrm{3}\) times the length. Which of the following is a possible value of \(\mathrm{x}\)?
1. TRANSLATE the problem information
- Given information:
- Rectangle has length x and width y (both positive)
- Area = 18 square units
- Perimeter = 3 times the length
- What this tells us:
- We need two equations: one for area, one for perimeter
2. TRANSLATE the conditions into equations
- Area condition: \(\mathrm{xy = 18}\)
- Perimeter condition: \(\mathrm{2x + 2y = 3x}\)
3. INFER the solution strategy
- We have two equations with two unknowns - this suggests using substitution
- The perimeter equation looks easier to solve for one variable first
4. SIMPLIFY the perimeter equation
- Start with: \(\mathrm{2x + 2y = 3x}\)
- Subtract 2x from both sides: \(\mathrm{2y = x}\)
- Divide by 2: \(\mathrm{y = x/2}\)
5. INFER the next step and SIMPLIFY
- Substitute \(\mathrm{y = x/2}\) into the area equation:
- \(\mathrm{x(x/2) = 18}\)
- \(\mathrm{x²/2 = 18}\)
- \(\mathrm{x² = 36}\)
- \(\mathrm{x = 6}\) (taking the positive root since length must be positive)
6. APPLY CONSTRAINTS to verify
- Check our solution: If \(\mathrm{x = 6}\), then \(\mathrm{y = x/2 = 3}\)
- Area check: \(\mathrm{6 × 3 = 18}\) ✓
- Perimeter check: \(\mathrm{2(6 + 3) = 18}\), and \(\mathrm{3 × 6 = 18}\) ✓
Answer: C (6)
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak TRANSLATE skill: Students misinterpret "perimeter is 3 times the length" as meaning the perimeter formula should be \(\mathrm{P = 3x}\), rather than setting the perimeter equal to 3x.
This leads them to write \(\mathrm{P = 3x}\) instead of \(\mathrm{2x + 2y = 3x}\), creating an incorrect equation. Without the proper relationship between x and y, they cannot solve the system and end up guessing.
Second Most Common Error:
Poor SIMPLIFY execution: Students correctly set up the equations but make algebraic errors when solving, such as:
- Getting \(\mathrm{y = 2x}\) instead of \(\mathrm{y = x/2}\) from the perimeter equation
- Making sign errors or calculation mistakes when solving \(\mathrm{x² = 36}\)
These errors lead to incorrect values that don't match any of the given choices, causing confusion and potentially selecting Choice A (4) or Choice D (9) through incorrect calculations.
The Bottom Line:
This problem requires careful translation of the perimeter condition and systematic algebraic manipulation. The key insight is recognizing that "perimeter equals 3 times the length" means \(\mathrm{2x + 2y = 3x}\), not that the perimeter formula itself is 3x.