A rectangle has a perimeter of 28 units. The length of the rectangle is 2 less than 3 times the...
GMAT Algebra : (Alg) Questions
A rectangle has a perimeter of \(28\) units. The length of the rectangle is \(2\) less than \(3\) times the width. What is the sum of the length and width of the rectangle?
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1. TRANSLATE the problem information
- Given information:
- Rectangle has perimeter of 28 units
- Length = 3 × width - 2
- Need to find: sum of length and width
- Set up variables: Let \(\mathrm{w}\) = width, \(\mathrm{l}\) = length
2. TRANSLATE each condition into equations
- From perimeter: \(\mathrm{2w + 2l = 28}\)
- Simplify by dividing by 2: \(\mathrm{w + l = 14}\)
- From length constraint: \(\mathrm{l = 3w - 2}\)
3. INFER the solution strategy
- We have two equations with two unknowns - this suggests using substitution
- Since we already have \(\mathrm{l}\) expressed in terms of \(\mathrm{w}\), substitute this into the perimeter equation
4. SIMPLIFY through substitution
- Substitute \(\mathrm{l = 3w - 2}\) into \(\mathrm{w + l = 14}\):
\(\mathrm{w + (3w - 2) = 14}\) - Combine like terms: \(\mathrm{4w - 2 = 14}\)
- Add 2 to both sides: \(\mathrm{4w = 16}\)
- Divide by 4: \(\mathrm{w = 4}\)
5. Find the length and calculate the sum
- \(\mathrm{l = 3(4) - 2 = 12 - 2 = 10}\)
- Sum = \(\mathrm{w + l = 4 + 10 = 14}\)
Answer: B (14)
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak TRANSLATE skill: Students often misinterpret "2 less than 3 times the width" and write \(\mathrm{l = 3w + 2}\) instead of \(\mathrm{l = 3w - 2}\).
This mistake changes the constraint equation, leading to different algebra:
\(\mathrm{w + (3w + 2) = 14}\)
\(\mathrm{4w + 2 = 14}\)
\(\mathrm{w = 3}\), \(\mathrm{l = 11}\), \(\mathrm{sum = 14}\)
Interestingly, this still gives the correct final answer due to the mathematical structure, but represents flawed reasoning that could fail in similar problems.
Second Most Common Error:
Poor SIMPLIFY execution: Students make arithmetic errors while solving \(\mathrm{4w - 2 = 14}\), such as getting \(\mathrm{w = 3}\) instead of \(\mathrm{w = 4}\).
With \(\mathrm{w = 3}\), they calculate \(\mathrm{l = 3(3) - 2 = 7}\), giving \(\mathrm{sum = 10}\). This may lead them to select Choice A (10).
The Bottom Line:
This problem tests whether students can systematically translate word constraints into algebra and then execute multi-step equation solving without computational errors. The key insight is recognizing that "2 less than" means subtraction, not addition.
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