prismlearning.academy Logo
NEUR
N

A rectangular field has a perimeter of 140 meters. The length of the field is 2 meters longer than its...

GMAT Geometry & Trigonometry : (Geo_Trig) Questions

Source: Prism
Geometry & Trigonometry
Area and volume formulas
EASY
...
...
Notes
Post a Query

A rectangular field has a perimeter of \(140\) meters. The length of the field is \(2\) meters longer than its width. What is the area of the field, in square meters?

A

1,156

B

1,200

C

1,224

D

1,260

Solution

1. TRANSLATE the problem information

  • Given information:
    • Perimeter = 140 meters
    • Length = width + 2 meters
    • Need to find: area
  • What this tells us: We have one constraint (perimeter) and one relationship between dimensions that should let us find both length and width.

2. INFER the approach

  • Since we have two unknowns (length and width) but know their relationship, we can use one variable
  • Let width = \(\mathrm{w}\), then length = \(\mathrm{w + 2}\)
  • Use the perimeter constraint to create an equation we can solve

3. TRANSLATE into mathematical expressions

  • Perimeter formula: \(\mathrm{P = 2(length + width)}\)
  • Substitute our expressions: \(\mathrm{140 = 2[(w + 2) + w]}\)

4. SIMPLIFY to solve for width

  • \(\mathrm{140 = 2(w + 2 + w)}\)
  • \(\mathrm{140 = 2(2w + 2)}\)
  • \(\mathrm{140 = 4w + 4}\)
  • \(\mathrm{136 = 4w}\)
  • \(\mathrm{w = 34}\) meters

5. Find length and calculate area

  • Width = 34 meters
  • Length = \(\mathrm{34 + 2 = 36}\) meters
  • Area = \(\mathrm{length \times width = 36 \times 34 = 1,224}\) square meters

Answer: (C) 1,224




Why Students Usually Falter on This Problem

Most Common Error Path:

Weak INFER skills: Students attempt to guess-and-check with the answer choices instead of setting up the algebraic relationship systematically.

They might try working backwards from each area value, but without the proper setup, they get confused about which dimensions correspond to which areas and end up guessing. This leads to random answer selection rather than systematic solution.

Second Most Common Error:

Poor SIMPLIFY execution: Students set up the equation correctly but make arithmetic errors when solving \(\mathrm{4w + 4 = 140}\).

Common mistakes include getting \(\mathrm{w = 32}\) (forgetting to subtract 4 first) or \(\mathrm{w = 36}\) (confusing which value is width vs length). If they get \(\mathrm{w = 32}\), then length = 34, giving area = \(\mathrm{32 \times 34 = 1,088}\), which doesn't match any answer choice and causes confusion.

The Bottom Line:

This problem tests whether students can translate a word problem into algebraic relationships and then execute the algebra correctly. The key insight is recognizing that one variable can represent both dimensions through their given relationship.

Answer Choices Explained
A

1,156

B

1,200

C

1,224

D

1,260

Rate this Solution
Tell us what you think about this solution
...
...
Forum Discussions
Start a new discussion
Post
Load More
Similar Questions
Finding similar questions...
Previous Attempts
Loading attempts...
Similar Questions
Finding similar questions...
Parallel Question Generator
Create AI-generated questions with similar patterns to master this question type.