A rectangular garden will be built using a rock wall as one side and a fence for the other three...
GMAT Advanced Math : (Adv_Math) Questions
A rectangular garden will be built using a rock wall as one side and a fence for the other three sides. The total length of the fence to be used is 80 meters. The function \(\mathrm{A(x) = 80x - 2x^2}\) gives the area of the garden \(\mathrm{A(x)}\), in square meters, where \(\mathrm{x}\) is the length, in meters, of each of the two fenced sides that are perpendicular to the wall. The graph of \(\mathrm{y = A(x)}\) in the xy-plane is a parabola that intersects the x-axis at \(\mathrm{x = 0}\) and at a positive value \(\mathrm{x = k}\). What does k represent in this context?
The length, in meters, of the perpendicular sides that results in the maximum area.
The length, in meters, of the side parallel to the wall that results in the maximum area.
The maximum area of the garden, in square meters.
The length, in meters, of the perpendicular sides that results in an area of 0 square meters.
1. TRANSLATE the problem information
- Given information:
- \(\mathrm{A(x) = 80x - 2x^2}\) represents the area of the garden
- \(\mathrm{x}\) represents the length of the two perpendicular sides (to the wall)
- The graph intersects the x-axis at \(\mathrm{x = 0}\) and \(\mathrm{x = k}\) (positive)
- We need to determine what k represents
2. INFER what an x-intercept means
- When a graph intersects the x-axis, the y-coordinate equals 0
- Since our graph shows \(\mathrm{y = A(x)}\), at \(\mathrm{x = k}\) we have \(\mathrm{A(k) = 0}\)
- This means k is the value of x where the area equals zero
3. SIMPLIFY to find the value of k
- Set the area function equal to zero: \(\mathrm{A(x) = 0}\)
- \(\mathrm{80x - 2x^2 = 0}\)
- Factor out 2x: \(\mathrm{2x(40 - x) = 0}\)
- This gives us \(\mathrm{x = 0}\) or \(\mathrm{x = 40}\)
- Since k is the positive x-intercept, \(\mathrm{k = 40}\)
4. INFER the physical meaning
- When \(\mathrm{x = 40}\) meters (perpendicular sides), the area is zero
- Check: If perpendicular sides are 40m each, that uses \(\mathrm{2(40) = 80m}\) of fence
- This leaves \(\mathrm{80 - 80 = 0}\) meters for the parallel side
- Result: A degenerate rectangle with zero area
Answer: D. The length, in meters, of the perpendicular sides that results in an area of 0 square meters.
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak INFER skill: Students may find \(\mathrm{k = 40}\) correctly but then confuse what this represents in context. They might think since 40 is a large number, it must represent the maximum area or the length that gives maximum area.
This confusion about interpreting the meaning of zero area may lead them to select Choice A (maximum area length) or Choice C (maximum area value).
Second Most Common Error:
Poor TRANSLATE reasoning: Students may misunderstand what the variable x represents in the function. If they think x is the parallel side length instead of the perpendicular sides, they'll misinterpret what k means entirely.
This misunderstanding of the variable definition may lead them to select Choice B (parallel side length) instead of recognizing it's about the perpendicular sides.
The Bottom Line:
This problem tests whether students can connect algebraic solutions (finding where a function equals zero) to real-world meaning (what it means for area to be zero in a geometry context). The key insight is that zero area occurs at a boundary condition where the rectangle becomes degenerate.
The length, in meters, of the perpendicular sides that results in the maximum area.
The length, in meters, of the side parallel to the wall that results in the maximum area.
The maximum area of the garden, in square meters.
The length, in meters, of the perpendicular sides that results in an area of 0 square meters.