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Question:A rectangular garden has length 3/4x + 5/2 meters and width 1/2x + 1/2 meters, where x is a positive...

GMAT Advanced Math : (Adv_Math) Questions

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Question:

  1. A rectangular garden has length \(\frac{3}{4}\mathrm{x} + \frac{5}{2}\) meters and width \(\frac{1}{2}\mathrm{x} + \frac{1}{2}\) meters, where \(\mathrm{x}\) is a positive real number.
  2. The area \(\mathrm{A(x)}\), in square meters, is the product of its length and width.
  3. When \(\mathrm{A(x)}\) is written in the form \(\mathrm{ax}^2 + \mathrm{bx} + \mathrm{c}\), where \(\mathrm{a}\), \(\mathrm{b}\), and \(\mathrm{c}\) are constants, what is the value of \(\mathrm{b}\)?
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Solution

1. TRANSLATE the problem information

  • Given information:
    • Length: \(\frac{3}{4}\mathrm{x} + \frac{5}{2}\) meters
    • Width: \(\frac{1}{2}\mathrm{x} + \frac{1}{2}\) meters
    • Area \(\mathrm{A(x)} = \text{length} \times \text{width}\)
    • Need coefficient b when \(\mathrm{A(x)}\) is written as \(\mathrm{ax}^2 + \mathrm{bx} + \mathrm{c}\)
  • What this tells us: We need to multiply the two binomials and find the coefficient of the x term.

2. SIMPLIFY by expanding the product

  • Set up the multiplication: \(\mathrm{A(x)} = \left(\frac{3}{4}\mathrm{x} + \frac{5}{2}\right)\left(\frac{1}{2}\mathrm{x} + \frac{1}{2}\right)\)
  • Use FOIL method:
    • First terms: \(\left(\frac{3}{4}\mathrm{x}\right)\left(\frac{1}{2}\mathrm{x}\right) = \frac{3}{8}\mathrm{x}^2\)
    • Outer terms: \(\left(\frac{3}{4}\mathrm{x}\right)\left(\frac{1}{2}\right) = \frac{3}{8}\mathrm{x}\)
    • Inner terms: \(\left(\frac{5}{2}\right)\left(\frac{1}{2}\mathrm{x}\right) = \frac{5}{4}\mathrm{x}\)
    • Last terms: \(\left(\frac{5}{2}\right)\left(\frac{1}{2}\right) = \frac{5}{4}\)

3. SIMPLIFY by combining like terms

  • Combine the x terms: \(\frac{3}{8}\mathrm{x} + \frac{5}{4}\mathrm{x}\)
  • Find common denominator: \(\frac{5}{4} = \frac{10}{8}\)
  • Add: \(\frac{3}{8}\mathrm{x} + \frac{10}{8}\mathrm{x} = \frac{13}{8}\mathrm{x}\)
  • Final form: \(\mathrm{A(x)} = \frac{3}{8}\mathrm{x}^2 + \frac{13}{8}\mathrm{x} + \frac{5}{4}\)

Answer: \(\frac{13}{8}\)


Why Students Usually Falter on This Problem

Most Common Error Path:

Weak SIMPLIFY execution: Students correctly expand using FOIL but make arithmetic errors when adding the fractions \(\frac{3}{8} + \frac{5}{4}\). They might add numerators directly (3 + 5 = 8) and denominators directly (8 + 4 = 12), getting \(\frac{8}{12} = \frac{2}{3}\), or they might incorrectly convert \(\frac{5}{4}\) to eighths as \(\frac{5}{8}\) instead of \(\frac{10}{8}\).

This leads to confusion and incorrect final answers.

Second Most Common Error:

Incomplete SIMPLIFY process: Students successfully use FOIL to get the four terms but forget to combine the like terms (\(\frac{3}{8}\mathrm{x}\) and \(\frac{5}{4}\mathrm{x}\)). They might report one of the individual coefficients (\(\frac{3}{8}\) or \(\frac{5}{4}\)) instead of their sum.

This causes them to provide a partial answer rather than the complete coefficient.

The Bottom Line:

This problem tests precision in fraction arithmetic within algebraic expansion. Success requires both systematic binomial multiplication and careful fraction addition with different denominators.

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