A rectangular garden plot has an area of 96 square feet. If the length of the garden is 4 feet...
GMAT Algebra : (Alg) Questions
A rectangular garden plot has an area of 96 square feet. If the length of the garden is 4 feet more than the width, what is the length, in feet, of the garden?
1. TRANSLATE the problem information
- Given information:
- Area of rectangular garden = \(96\) square feet
- Length = width + \(4\) feet
- Find: the length
- What this tells us: We have one unknown (width) that determines both dimensions
2. INFER the approach
- Since we know area and the relationship between length and width, we can set up one equation with one unknown
- Let width = \(\mathrm{w}\), so length = \(\mathrm{(w + 4)}\)
3. TRANSLATE into mathematical equation
- Using Area = length × width:
\(\mathrm{96 = (w + 4) \times w}\)
\(\mathrm{96 = w^2 + 4w}\)
4. SIMPLIFY to solve the quadratic
- Rearrange to standard form: \(\mathrm{w^2 + 4w - 96 = 0}\)
- Factor by finding two numbers that multiply to \(-96\) and add to \(4\)
- Those numbers are \(12\) and \(-8\): \(\mathrm{(w + 12)(w - 8) = 0}\)
- Solutions: \(\mathrm{w = -12}\) or \(\mathrm{w = 8}\)
5. APPLY CONSTRAINTS to select valid solution
- Since width represents a physical dimension, it must be positive
- Therefore: \(\mathrm{w = 8}\) feet
- Length = \(\mathrm{w + 4 = 8 + 4 = 12}\) feet
Answer: 12
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak TRANSLATE skill: Students might set up the length relationship backwards, writing length = \(\mathrm{w - 4}\) instead of \(\mathrm{w + 4}\), or confuse which dimension is which.
This leads to the equation \(\mathrm{96 = w(w - 4) = w^2 - 4w}\), giving \(\mathrm{w^2 - 4w - 96 = 0}\). Factoring gives \(\mathrm{(w - 12)(w + 8) = 0}\), so \(\mathrm{w = 12}\) or \(\mathrm{w = -8}\). Taking the positive solution gives width = \(12\), so length = \(\mathrm{12 - 4 = 8}\). This backwards answer might cause confusion or lead to guessing.
Second Most Common Error:
Poor SIMPLIFY execution: Students might make algebraic errors when expanding \(\mathrm{w(w + 4)}\) or when factoring the quadratic equation.
For example, they might incorrectly expand to get \(\mathrm{w^2 + 4}\) instead of \(\mathrm{w^2 + 4w}\), or struggle with factoring and resort to guessing factors. This leads to confusion and random answer selection.
The Bottom Line:
This problem requires careful translation of the word relationship into algebra, systematic quadratic solving, and remembering that real-world dimensions must make sense. The key insight is recognizing that "4 feet more than" means addition, not subtraction.