A rectangular photograph has an area of 900 square centimeters. A photo lab creates a reduced copy of this photograph...
GMAT Geometry & Trigonometry : (Geo_Trig) Questions
A rectangular photograph has an area of \(900\) square centimeters. A photo lab creates a reduced copy of this photograph where the length of each side of the reduced copy is \(\frac{1}{5}\) times the length of the corresponding side of the original photograph. What is the area, in square centimeters, of the reduced copy?
- \(36\)
- \(45\)
- \(90\)
- \(180\)
\(\mathrm{36}\)
\(\mathrm{45}\)
\(\mathrm{90}\)
\(\mathrm{180}\)
1. TRANSLATE the problem information
- Given information:
- Original photograph area: \(\mathrm{900}\) square centimeters
- Each side of reduced copy is \(\mathrm{\frac{1}{5}}\) times the corresponding side of original
- Need to find the area of the reduced copy
2. INFER the scaling relationship
- The key insight: When a 2D figure is scaled, the area doesn't scale the same way as the sides
- If linear dimensions scale by factor \(\mathrm{k}\), then area scales by \(\mathrm{k^2}\)
- This happens because area involves \(\mathrm{length \times width}\), so both dimensions get multiplied by \(\mathrm{k}\)
3. SIMPLIFY to find the area scale factor
- Linear scale factor: \(\mathrm{k = \frac{1}{5}}\)
- Area scale factor: \(\mathrm{k^2 = (\frac{1}{5})^2 = \frac{1}{25}}\)
4. SIMPLIFY to calculate the final area
- Area of reduced copy = Original area × Area scale factor
- Area of reduced copy = \(\mathrm{900 \times \frac{1}{25} = 900 \div 25 = 36}\) square centimeters
Answer: A (36)
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak INFER skill: Students assume that area scales linearly with the sides
Many students think: "If each side is \(\mathrm{\frac{1}{5}}\) the original, then the area should also be \(\mathrm{\frac{1}{5}}\) the original." This linear thinking ignores the fact that area is a 2-dimensional measurement.
Following this incorrect reasoning: \(\mathrm{900 \times \frac{1}{5} = 180}\)
This may lead them to select Choice D (180)
Second Most Common Error:
Inadequate SIMPLIFY execution: Students correctly identify that area scales by \(\mathrm{(\frac{1}{5})^2}\), but make calculation errors
They might incorrectly calculate \(\mathrm{(\frac{1}{5})^2}\) or make arithmetic errors in the final multiplication, leading to confusion and potentially guessing among the remaining choices.
The Bottom Line:
This problem tests whether students understand the fundamental difference between linear scaling and area scaling. The critical insight is recognizing that area is a 2-dimensional quantity, so when you scale both length and width by the same factor, the area changes by that factor squared.
\(\mathrm{36}\)
\(\mathrm{45}\)
\(\mathrm{90}\)
\(\mathrm{180}\)