A rectangular storage container has a total surface area of 254 square inches. The length of the container is 9...
GMAT Geometry & Trigonometry : (Geo_Trig) Questions
A rectangular storage container has a total surface area of \(254\) square inches. The length of the container is \(9\) inches and the width is \(7\) inches. What is the height, in inches, of the container?
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1. TRANSLATE the problem information
- Given information:
- Surface area = 254 square inches
- Length = 9 inches
- Width = 7 inches
- Find: height
- What this tells us: We need to use the surface area formula to find the missing dimension.
2. INFER the correct approach
- Since we have a rectangular container with known surface area, we need the surface area formula: \(\mathrm{SA = 2(lw + lh + wh)}\)
- Strategy: Substitute known values and solve for height (h)
3. TRANSLATE into mathematical equation
Set up the equation:
\(\mathrm{254 = 2(9×7 + 9h + 7h)}\)
4. SIMPLIFY step by step
- First, calculate the known area: \(\mathrm{9×7 = 63}\)
- Combine like terms with h: \(\mathrm{9h + 7h = 16h}\)
- Equation becomes: \(\mathrm{254 = 2(63 + 16h)}\)
- Distribute the 2: \(\mathrm{254 = 126 + 32h}\)
- Subtract 126 from both sides: \(\mathrm{128 = 32h}\)
- Divide by 32: \(\mathrm{h = 4}\)
Answer: B) 4
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak INFER skill: Students may confuse surface area with volume and use \(\mathrm{V = lwh}\) instead of the surface area formula.
Using volume formula: \(\mathrm{254 = 9×7×h = 63h}\), so \(\mathrm{h = 254/63 ≈ 4.03}\), leading them to round to 4. While this accidentally gives the right answer choice, it's based on wrong reasoning and wouldn't work for other problems.
Second Most Common Error:
Poor SIMPLIFY execution: Students make algebraic errors, particularly when distributing the 2 or combining like terms.
For example, incorrectly getting \(\mathrm{254 = 2(63) + 16h}\) instead of \(\mathrm{254 = 2(63 + 16h)}\), leading to \(\mathrm{254 = 126 + 16h}\), then \(\mathrm{128 = 16h}\), so \(\mathrm{h = 8}\). This leads them to select Choice D (8).
The Bottom Line:
This problem requires careful attention to which formula applies (surface area vs volume) and methodical algebraic manipulation. The key insight is recognizing that a rectangular container's surface area includes all six faces.
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