A ride-hailing service charges a fixed fee f dollars per ride and an additional m dollars per mile. A 0-mile...
GMAT Algebra : (Alg) Questions
A ride-hailing service charges a fixed fee \(\mathrm{f}\) dollars per ride and an additional \(\mathrm{m}\) dollars per mile. A \(0\)-mile ride costs \(\$7\), and a \(3\)-mile ride costs \(\$19\). What is the value of \(\mathrm{m}\)?
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1. TRANSLATE the problem information
- Given information:
- Fixed fee \(\mathrm{f}\) dollars per ride, plus \(\mathrm{m}\) dollars per mile
- 0-mile ride costs $7
- 3-mile ride costs $19
- Need to find \(\mathrm{m}\)
- What this tells us: We have a linear cost function where \(\mathrm{total\ cost = f + m \times (miles)}\)
2. INFER the solving strategy
- Key insight: The 0-mile ride gives us the fixed fee directly since there's no mileage charge
- Strategy: Use the first scenario to find \(\mathrm{f}\), then use the second scenario to find \(\mathrm{m}\)
3. TRANSLATE each scenario into equations
- For 0-mile ride: \(\mathrm{f + m(0) = 7}\), which simplifies to \(\mathrm{f = 7}\)
- For 3-mile ride: \(\mathrm{f + m(3) = 19}\)
4. SIMPLIFY by substituting and solving
- Substitute \(\mathrm{f = 7}\) into the second equation: \(\mathrm{7 + 3m = 19}\)
- Subtract 7 from both sides: \(\mathrm{3m = 12}\)
- Divide by 3: \(\mathrm{m = 4}\)
Answer: C) 4
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak TRANSLATE skill: Students may set up incorrect equations by not clearly understanding what the "0-mile ride" scenario represents.
Some students might think they need to solve a complex system of equations instead of recognizing that \(\mathrm{f + m(0) = 7}\) simply means \(\mathrm{f = 7}\). They may write something like "\(\mathrm{f + 0m = 7}\) and \(\mathrm{f + 3m = 19}\)" but then get confused about how to proceed systematically.
This leads to confusion and guessing among the answer choices.
Second Most Common Error:
Poor SIMPLIFY execution: Students set up the equations correctly but make arithmetic errors when solving.
They might correctly get to \(\mathrm{7 + 3m = 19}\), but then make errors like: \(\mathrm{3m = 19 + 7 = 26}\), so \(\mathrm{m = 26/3}\), or other calculation mistakes. Since none of the answer choices match these incorrect calculations, they end up guessing.
This may lead them to select Choice A (2) or Choice D (6) as "reasonable-looking" answers.
The Bottom Line:
This problem tests whether students can translate a real-world linear relationship into mathematics and recognize that one scenario can directly give them part of the solution, making the rest straightforward.
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