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A right circular cylinder has a circular base with circumference 8pi inches and a height of 12 inches. What is...

GMAT Geometry & Trigonometry : (Geo_Trig) Questions

Source: Prism
Geometry & Trigonometry
Area and volume formulas
MEDIUM
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Notes
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A right circular cylinder has a circular base with circumference \(8\pi\) inches and a height of \(12\) inches. What is the volume, in cubic inches, of the cylinder?

  1. \(48\pi\)
  2. \(96\pi\)
  3. \(192\pi\)
  4. \(768\pi\)
A
\(48\pi\)
B
\(96\pi\)
C
\(192\pi\)
D
\(768\pi\)
Solution

1. TRANSLATE the problem information

  • Given information:
    • Right circular cylinder with circumference = \(8\pi\) inches
    • Height = 12 inches
    • Need to find: volume in cubic inches

2. INFER the solution strategy

  • To find volume of a cylinder, we need the radius and height
  • We have the height (12 inches) but need to find the radius
  • We can use the given circumference to find the radius first

3. SIMPLIFY to find the radius

  • Use the circumference formula: \(\mathrm{C} = 2\pi\mathrm{r}\)
  • Substitute known values: \(8\pi = 2\pi\mathrm{r}\)
  • Divide both sides by \(2\pi\): \(\mathrm{r} = \frac{8\pi}{2\pi} = 4\) inches

4. SIMPLIFY to calculate the volume

  • Use cylinder volume formula: \(\mathrm{V} = \pi\mathrm{r}^2\mathrm{h}\)
  • Substitute our values: \(\mathrm{V} = \pi(4)^2(12)\)
  • Calculate: \(\mathrm{V} = \pi(16)(12) = 192\pi\) cubic inches

Answer: C (\(192\pi\))


Why Students Usually Falter on This Problem

Most Common Error Path:

Conceptual confusion about radius vs diameter: Students might incorrectly think the circumference represents the diameter, leading them to use \(\mathrm{r} = 8\) instead of \(\mathrm{r} = 4\).

This would give \(\mathrm{V} = \pi(8)^2(12) = \pi(64)(12) = 768\pi\), causing them to select Choice D (\(768\pi\)).

Second Most Common Error:

Weak SIMPLIFY execution: Students correctly find \(\mathrm{r} = 4\) but forget to square the radius in the volume formula, calculating \(\mathrm{V} = \pi(4)(12)\) instead of \(\mathrm{V} = \pi(4)^2(12)\).

This gives \(\mathrm{V} = 48\pi\), leading them to select Choice A (\(48\pi\)).

The Bottom Line:

This problem tests whether students can work backwards from circumference to radius, then forwards to volume. The key insight is recognizing that circumference gives you the radius through \(\mathrm{C} = 2\pi\mathrm{r}\), not that circumference equals diameter.

Answer Choices Explained
A
\(48\pi\)
B
\(96\pi\)
C
\(192\pi\)
D
\(768\pi\)
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