A right circular cylinder has a circular base with circumference 8pi inches and a height of 12 inches. What is...
GMAT Geometry & Trigonometry : (Geo_Trig) Questions
A right circular cylinder has a circular base with circumference \(8\pi\) inches and a height of \(12\) inches. What is the volume, in cubic inches, of the cylinder?
- \(48\pi\)
- \(96\pi\)
- \(192\pi\)
- \(768\pi\)
1. TRANSLATE the problem information
- Given information:
- Right circular cylinder with circumference = \(8\pi\) inches
- Height = 12 inches
- Need to find: volume in cubic inches
2. INFER the solution strategy
- To find volume of a cylinder, we need the radius and height
- We have the height (12 inches) but need to find the radius
- We can use the given circumference to find the radius first
3. SIMPLIFY to find the radius
- Use the circumference formula: \(\mathrm{C} = 2\pi\mathrm{r}\)
- Substitute known values: \(8\pi = 2\pi\mathrm{r}\)
- Divide both sides by \(2\pi\): \(\mathrm{r} = \frac{8\pi}{2\pi} = 4\) inches
4. SIMPLIFY to calculate the volume
- Use cylinder volume formula: \(\mathrm{V} = \pi\mathrm{r}^2\mathrm{h}\)
- Substitute our values: \(\mathrm{V} = \pi(4)^2(12)\)
- Calculate: \(\mathrm{V} = \pi(16)(12) = 192\pi\) cubic inches
Answer: C (\(192\pi\))
Why Students Usually Falter on This Problem
Most Common Error Path:
Conceptual confusion about radius vs diameter: Students might incorrectly think the circumference represents the diameter, leading them to use \(\mathrm{r} = 8\) instead of \(\mathrm{r} = 4\).
This would give \(\mathrm{V} = \pi(8)^2(12) = \pi(64)(12) = 768\pi\), causing them to select Choice D (\(768\pi\)).
Second Most Common Error:
Weak SIMPLIFY execution: Students correctly find \(\mathrm{r} = 4\) but forget to square the radius in the volume formula, calculating \(\mathrm{V} = \pi(4)(12)\) instead of \(\mathrm{V} = \pi(4)^2(12)\).
This gives \(\mathrm{V} = 48\pi\), leading them to select Choice A (\(48\pi\)).
The Bottom Line:
This problem tests whether students can work backwards from circumference to radius, then forwards to volume. The key insight is recognizing that circumference gives you the radius through \(\mathrm{C} = 2\pi\mathrm{r}\), not that circumference equals diameter.