prismlearning.academy Logo
NEUR
N

An architect is designing a wheelchair ramp that will lead up to the entrance of a library. The ramp forms...

GMAT Geometry & Trigonometry : (Geo_Trig) Questions

Source: Prism
Geometry & Trigonometry
Right triangles and trigonometry
MEDIUM
...
...
Notes
Post a Query

An architect is designing a wheelchair ramp that will lead up to the entrance of a library. The ramp forms a right triangle with the level ground and the vertical wall of the library. The angle the ramp makes with the ground is \(\alpha\), and \(\cos \alpha = \frac{3}{5}\). If the horizontal distance from the start of the ramp to the base of the wall is 60 feet, what is the length, in feet, of the ramp itself?

A

36

B

75

C

100

D

120

Solution

1. TRANSLATE the problem information

  • Given information:
    • The ramp, ground, and wall form a right triangle
    • Angle α is between the ramp and ground
    • \(\cos \alpha = \frac{3}{5}\)
    • Horizontal distance from start of ramp to wall = 60 feet
    • Need to find: length of ramp (hypotenuse)

2. INFER the approach

  • The key insight: we can use the cosine ratio directly since we know the angle's cosine value and the adjacent side
  • We don't need to find the opposite side or the actual angle measure
  • Set up: \(\cos \alpha = \frac{\mathrm{adjacent}}{\mathrm{hypotenuse}}\)

3. TRANSLATE into the equation

  • \(\cos \alpha = \frac{\mathrm{adjacent}}{\mathrm{hypotenuse}}\) becomes:
  • \(\frac{3}{5} = \frac{60}{\mathrm{hypotenuse}}\)

4. SIMPLIFY to solve for the hypotenuse

  • Cross multiply: \(3 \times \mathrm{hypotenuse} = 5 \times 60\)
  • \(3 \times \mathrm{hypotenuse} = 300\)
  • \(\mathrm{hypotenuse} = 300 \div 3 = 100\)

Answer: C. 100




Why Students Usually Falter on This Problem

Most Common Error Path:

Weak TRANSLATE reasoning: Students often confuse which side is which in the right triangle setup. They might think the 60 feet is the hypotenuse or the opposite side instead of recognizing it as the adjacent side to angle α.

When they set up \(\cos \alpha = \frac{60}{\mathrm{hypotenuse}}\) (thinking 60 is the hypotenuse), they get \(\frac{3}{5} = \frac{60}{\mathrm{hypotenuse}}\), leading to \(\mathrm{hypotenuse} = 60 \times \frac{3}{5} = 36\).

This leads them to select Choice A (36).

Second Most Common Error:

Poor INFER strategy: Students recognize the setup correctly but think they need to find the actual angle first, then use it somehow. They might try to calculate \(\alpha = \arccos(\frac{3}{5}) \approx 53.13°\), then get confused about what to do next.

This causes them to get stuck and abandon their systematic approach, often guessing among the remaining choices.

The Bottom Line:

The challenge is recognizing that trigonometric ratios can be used directly with given ratio values - you don't always need to find the actual angle measure. The problem gives you everything needed to apply the cosine definition immediately.

Answer Choices Explained
A

36

B

75

C

100

D

120

Rate this Solution
Tell us what you think about this solution
...
...
Forum Discussions
Start a new discussion
Post
Load More
Similar Questions
Finding similar questions...
Previous Attempts
Loading attempts...
Similar Questions
Finding similar questions...
Parallel Question Generator
Create AI-generated questions with similar patterns to master this question type.