A right triangle has legs with lengths of 11 centimeters and 9 centimeters. What is the length of this triangle's...
GMAT Geometry & Trigonometry : (Geo_Trig) Questions
A right triangle has legs with lengths of \(11\) centimeters and \(9\) centimeters. What is the length of this triangle's hypotenuse, in centimeters?
\(\sqrt{40}\)
\(\sqrt{202}\)
\(20\)
\(202\)
1. TRANSLATE the problem information
- Given information:
- Right triangle with legs of 11 cm and 9 cm
- Need to find the hypotenuse length
- This tells us we need to use the Pythagorean theorem: \(\mathrm{c^2 = a^2 + b^2}\)
2. TRANSLATE the setup into the equation
- In the Pythagorean theorem \(\mathrm{c^2 = a^2 + b^2}\):
- c represents the hypotenuse (what we're finding)
- a and b represent the two legs (11 cm and 9 cm)
- Substituting: \(\mathrm{c^2 = 11^2 + 9^2}\)
3. SIMPLIFY the calculation
- Calculate each square:
- \(\mathrm{11^2 = 121}\)
- \(\mathrm{9^2 = 81}\)
- Add them: \(\mathrm{c^2 = 121 + 81 = 202}\)
- Take the square root: \(\mathrm{c = \sqrt{202}}\)
4. APPLY CONSTRAINTS to finalize the answer
- Since c represents a length, it must be positive
- Therefore: \(\mathrm{c = \sqrt{202}}\) cm
Answer: B. \(\mathrm{\sqrt{202}}\)
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak TRANSLATE skill: Students confuse squaring numbers with doubling them, setting up \(\mathrm{c^2 = 11(2) + 9(2)}\) instead of \(\mathrm{c^2 = 11^2 + 9^2}\)
When they calculate: \(\mathrm{c^2 = 22 + 18 = 40}\), so \(\mathrm{c = \sqrt{40}}\)
This leads them to select Choice A (\(\mathrm{\sqrt{40}}\))
Second Most Common Error:
Poor TRANSLATE reasoning: Students set up the equation incorrectly as \(\mathrm{c = 11^2 + 9^2}\) instead of \(\mathrm{c^2 = 11^2 + 9^2}\)
When they calculate: \(\mathrm{c = 121 + 81 = 202}\)
This leads them to select Choice D (202)
The Bottom Line:
The Pythagorean theorem requires precise setup - it's c² (c squared) equals the sum of the squares of the legs, not c equals the sum or any other variation. The mathematical notation must be translated correctly from the conceptual understanding.
\(\sqrt{40}\)
\(\sqrt{202}\)
\(20\)
\(202\)