Which expression is equivalent to \(-1(3\mathrm{x}^2 - \mathrm{x} + 5) + (4\mathrm{x}^2 - 2\mathrm{x} - 8)\)?-{x^2 - 3x + 13}x^2...
GMAT Advanced Math : (Adv_Math) Questions
Which expression is equivalent to \(-1(3\mathrm{x}^2 - \mathrm{x} + 5) + (4\mathrm{x}^2 - 2\mathrm{x} - 8)\)?
- \(-\mathrm{x}^2 - 3\mathrm{x} + 13\)
- \(\mathrm{x}^2 - \mathrm{x} - 13\)
- \(\mathrm{x}^2 + \mathrm{x} - 13\)
- \(7\mathrm{x}^2 - \mathrm{x} - 3\)
1. SIMPLIFY by applying the distributive property
- First, distribute -1 to every term in the first polynomial:
\(-1(3\mathrm{x}^2 - \mathrm{x} + 5) = -3\mathrm{x}^2 + \mathrm{x} - 5\)
- Keep the second polynomial as is: \((4\mathrm{x}^2 - 2\mathrm{x} - 8)\)
2. VISUALIZE by organizing like terms
- Write out the complete expression:
\(-3\mathrm{x}^2 + \mathrm{x} - 5 + 4\mathrm{x}^2 - 2\mathrm{x} - 8\)
- Group terms by degree and variable:
\((-3\mathrm{x}^2 + 4\mathrm{x}^2) + (\mathrm{x} - 2\mathrm{x}) + (-5 - 8)\)
3. SIMPLIFY by combining like terms
- x² terms: \(-3\mathrm{x}^2 + 4\mathrm{x}^2 = 1\mathrm{x}^2 = \mathrm{x}^2\)
- x terms: \(\mathrm{x} - 2\mathrm{x} = -1\mathrm{x} = -\mathrm{x}\)
- Constants: \(-5 - 8 = -13\)
- Final result: \(\mathrm{x}^2 - \mathrm{x} - 13\)
Answer: B
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak SIMPLIFY execution: Sign errors when distributing the negative coefficient
Students often make mistakes like:
- \(-1(3\mathrm{x}^2 - \mathrm{x} + 5) = -3\mathrm{x}^2 + \mathrm{x} + 5\) (forgetting to make the +5 negative)
- \(-1(3\mathrm{x}^2 - \mathrm{x} + 5) = -3\mathrm{x}^2 - \mathrm{x} - 5\) (making the -x term negative when it should become positive)
These sign errors cascade through the rest of the problem, potentially leading them to select Choice A (\(-\mathrm{x}^2 - 3\mathrm{x} + 13\)) or getting completely different coefficients.
Second Most Common Error:
Poor VISUALIZE organization: Not properly grouping like terms before combining
Students might combine terms haphazardly without systematic organization:
- Combining x² with x terms
- Missing terms during the combination process
- Getting confused about which terms can be combined
This leads to coefficient errors and may result in selecting Choice C (\(\mathrm{x}^2 + \mathrm{x} - 13\)) where the middle term sign is wrong.
The Bottom Line:
This problem tests careful execution of fundamental algebra skills. Success requires methodical distribution of negative coefficients and systematic organization when combining multiple like terms.