The formula to convert temperature from Celsius to Fahrenheit is F = 9/5C + 32. What is the temperature in...
GMAT Algebra : (Alg) Questions
The formula to convert temperature from Celsius to Fahrenheit is \(\mathrm{F} = \frac{9}{5}\mathrm{C} + 32\). What is the temperature in Fahrenheit when the temperature is \(25\) degrees Celsius?
- 45
- 57
- 77
- 89
1. TRANSLATE the problem information
- Given information:
- Conversion formula: \(\mathrm{F = \frac{9}{5}C + 32}\)
- Temperature in Celsius: \(\mathrm{C = 25°}\)
- Need to find: Temperature in Fahrenheit (F)
2. TRANSLATE the approach
- The phrase "when the temperature is 25 degrees Celsius" tells us to substitute \(\mathrm{C = 25}\) into our formula
- We'll replace C with 25 and calculate F
3. SIMPLIFY through substitution and calculation
- Substitute: \(\mathrm{F = \frac{9}{5}(25) + 32}\)
- Follow order of operations - multiplication before addition:
- First: \(\mathrm{\frac{9}{5} \times 25 = \frac{9 \times 25}{5} = \frac{225}{5} = 45}\)
- Then: \(\mathrm{45 + 32 = 77}\)
Answer: \(\mathrm{77°F}\) (Choice C)
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak SIMPLIFY execution: Students correctly set up the substitution but make arithmetic errors in calculating \(\mathrm{\frac{9}{5} \times 25}\), often getting confused by the fraction multiplication or forgetting to add 32 at the end.
Some students calculate \(\mathrm{\frac{9}{5} \times 25 = 45}\) correctly but then forget the final step of adding 32, leading them to select Choice A (45).
Second Most Common Error:
Poor TRANSLATE reasoning: Students misinterpret the conversion process and simply add 32 to the Celsius temperature without applying the \(\mathrm{\frac{9}{5}}\) multiplication factor.
This leads to \(\mathrm{25 + 32 = 57}\), causing them to select Choice B (57).
The Bottom Line:
Temperature conversion problems require careful attention to both the complete formula and precise arithmetic execution. Success depends on systematic substitution followed by accurate multi-step calculations.