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The formula to convert temperature from Celsius to Fahrenheit is F = 9/5C + 32. What is the temperature in...

GMAT Algebra : (Alg) Questions

Source: Prism
Algebra
Linear functions
EASY
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Notes
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The formula to convert temperature from Celsius to Fahrenheit is \(\mathrm{F} = \frac{9}{5}\mathrm{C} + 32\). What is the temperature in Fahrenheit when the temperature is \(25\) degrees Celsius?

  1. 45
  2. 57
  3. 77
  4. 89
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Solution

1. TRANSLATE the problem information

  • Given information:
    • Conversion formula: \(\mathrm{F = \frac{9}{5}C + 32}\)
    • Temperature in Celsius: \(\mathrm{C = 25°}\)
    • Need to find: Temperature in Fahrenheit (F)

2. TRANSLATE the approach

  • The phrase "when the temperature is 25 degrees Celsius" tells us to substitute \(\mathrm{C = 25}\) into our formula
  • We'll replace C with 25 and calculate F

3. SIMPLIFY through substitution and calculation

  • Substitute: \(\mathrm{F = \frac{9}{5}(25) + 32}\)
  • Follow order of operations - multiplication before addition:
    • First: \(\mathrm{\frac{9}{5} \times 25 = \frac{9 \times 25}{5} = \frac{225}{5} = 45}\)
    • Then: \(\mathrm{45 + 32 = 77}\)

Answer: \(\mathrm{77°F}\) (Choice C)




Why Students Usually Falter on This Problem


Most Common Error Path:

Weak SIMPLIFY execution: Students correctly set up the substitution but make arithmetic errors in calculating \(\mathrm{\frac{9}{5} \times 25}\), often getting confused by the fraction multiplication or forgetting to add 32 at the end.

Some students calculate \(\mathrm{\frac{9}{5} \times 25 = 45}\) correctly but then forget the final step of adding 32, leading them to select Choice A (45).


Second Most Common Error:

Poor TRANSLATE reasoning: Students misinterpret the conversion process and simply add 32 to the Celsius temperature without applying the \(\mathrm{\frac{9}{5}}\) multiplication factor.

This leads to \(\mathrm{25 + 32 = 57}\), causing them to select Choice B (57).


The Bottom Line:

Temperature conversion problems require careful attention to both the complete formula and precise arithmetic execution. Success depends on systematic substitution followed by accurate multi-step calculations.

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