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Question:The table shows four values of x and their corresponding values of \(\mathrm{p(x)}\). There is a relationship between x and...

GMAT Algebra : (Alg) Questions

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Algebra
Linear functions
MEDIUM
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Question:

The table shows four values of \(\mathrm{x}\) and their corresponding values of \(\mathrm{p(x)}\). There is a relationship between \(\mathrm{x}\) and \(\mathrm{p(x)}\) that is defined by the equation \(\mathrm{p(x) = \frac{k}{x} + 7}\), where \(\mathrm{k}\) is a constant. What is the value of \(\mathrm{k}\)?

\(\mathrm{x}\)3456
\(\mathrm{p(x)}\)27221917
  1. 20
  2. 27
  3. 60
  4. 81
  5. 102
Enter your answer here
Solution

1. TRANSLATE the problem information

  • Given information:
    • Table of x and p(x) values: \(\(3,27\)\), \(\(4,22\)\), \(\(5,19\)\), \(\(6,17\)\)
    • Equation form: \(\mathrm{p(x) = \frac{k}{x} + 7}\)
    • Need to find constant k
  • What this tells us: Any coordinate pair from the table must satisfy the equation

2. INFER the solution strategy

  • Since any point on the table satisfies the equation, we can substitute any coordinate pair
  • Choose the simplest point to work with - let's use \(\(3, 27\)\)
  • Substitute \(\mathrm{x = 3}\) and \(\mathrm{p(x) = 27}\) into \(\mathrm{p(x) = \frac{k}{x} + 7}\)

3. SIMPLIFY the algebraic equation

  • Start with: \(\mathrm{27 = \frac{k}{3} + 7}\)
  • Subtract 7 from both sides: \(\mathrm{27 - 7 = \frac{k}{3}}\)
  • Simplify: \(\mathrm{20 = \frac{k}{3}}\)
  • Multiply both sides by 3: \(\mathrm{k = 60}\)

4. Verify the solution

  • Test with another point, say \(\(4, 22\)\):
  • \(\mathrm{p(4) = \frac{60}{4} + 7 = 15 + 7 = 22}\)

Answer: C) 60




Why Students Usually Falter on This Problem

Most Common Error Path:

Weak SIMPLIFY execution: Students make arithmetic mistakes when isolating k, particularly when working with fractions or negative numbers.

For example, they might incorrectly solve \(\mathrm{27 = \frac{k}{3} + 7}\) by writing \(\mathrm{27 + 7 = \frac{k}{3}}\) instead of \(\mathrm{27 - 7 = \frac{k}{3}}\), leading to \(\mathrm{34 = \frac{k}{3}}\) and \(\mathrm{k = 102}\). This may lead them to select Choice E (102).

Second Most Common Error:

Poor TRANSLATE reasoning: Students might not recognize that they can use any point from the table, or they might substitute the values incorrectly into the equation.

Some students might switch x and p(x) values, substituting \(\mathrm{3 = \frac{k}{27} + 7}\) instead of \(\mathrm{27 = \frac{k}{3} + 7}\). This leads to completely different arithmetic and confusion about which answer choice to select.

The Bottom Line:

This problem tests whether students can systematically substitute known values into an equation and solve for an unknown constant - a fundamental skill in working with functions that have parameters.

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