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Problem:Square X has a side length of 12 centimeters. The perimeter of square Y is 2 times the perimeter of...

GMAT Geometry & Trigonometry : (Geo_Trig) Questions

Source: Practice Test
Geometry & Trigonometry
Area and volume formulas
MEDIUM
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Notes
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Problem:

Square X has a side length of \(12\) centimeters. The perimeter of square Y is \(2\) times the perimeter of square X. What is the length, in centimeters, of one side of square Y?

A

\(\mathrm{6}\)

B

\(\mathrm{10}\)

C

\(\mathrm{14}\)

D

\(\mathrm{24}\)

Solution

1. TRANSLATE the problem information

  • Given information:
    • Square X has side length = 12 cm
    • Perimeter of square Y = 2 × (perimeter of square X)
    • Need to find: side length of square Y

2. INFER the approach

  • We need to work in stages: find X's perimeter → find Y's perimeter → find Y's side length
  • This requires using the perimeter formula twice: once forward, once backward

3. Calculate the perimeter of square X

  • Using \(\mathrm{P = 4s}\): \(\mathrm{P_X = 4(12) = 48}\) cm

4. TRANSLATE to find Y's perimeter

  • "2 times the perimeter of square X" means: \(\mathrm{P_Y = 2 \times 48 = 96}\) cm

5. SIMPLIFY to find Y's side length

  • We know \(\mathrm{P_Y = 96}\) and \(\mathrm{P = 4s}\) for any square
  • So: \(\mathrm{96 = 4s}\)
  • Divide both sides by 4: \(\mathrm{s = 24}\) cm

Answer: D. 24




Why Students Usually Falter on This Problem

Most Common Error Path:

Weak TRANSLATE skill: Students misinterpret "2 times the perimeter of square X" as "2 times the side length of square X"

They calculate: Side of Y = \(\mathrm{2 \times 12 = 24}\), but then think this IS the final answer without checking it makes sense with perimeter relationships. Or they might calculate \(\mathrm{2 \times 12 = 24}\), then think they need to do something else with it, leading to confusion.

This may lead them to select Choice D (24) for the wrong reasoning, or get confused and guess other answers.

Second Most Common Error:

Poor SIMPLIFY execution: Students correctly find that square Y has perimeter 96 cm, but make arithmetic errors when solving \(\mathrm{96 = 4s}\)

They might calculate \(\mathrm{96 \div 4}\) incorrectly, especially if rushing, or set up the division wrong.

This causes them to get stuck or select Choice A (6) or Choice C (14) from calculation errors.

The Bottom Line:

This problem tests whether students can follow a multi-step logical chain while carefully translating English phrases into correct mathematical relationships. The key insight is recognizing that you must work with perimeters first, not jump directly to side lengths.

Answer Choices Explained
A

\(\mathrm{6}\)

B

\(\mathrm{10}\)

C

\(\mathrm{14}\)

D

\(\mathrm{24}\)

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