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A storage tank initially contains 300 gallons of water. The water is drained from the tank at a constant rate...

GMAT Algebra : (Alg) Questions

Source: Prism
Algebra
Linear functions
EASY
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A storage tank initially contains 300 gallons of water. The water is drained from the tank at a constant rate of 15 gallons per minute. Which equation represents this situation, where \(\mathrm{w}\) is the amount of water, in gallons, remaining in the tank after \(\mathrm{t}\) minutes?

A

\(\mathrm{w = 285t}\)

B

\(\mathrm{w = 15t - 300}\)

C

\(\mathrm{w = 300 + 15t}\)

D

\(\mathrm{w = 300 - 15t}\)

Solution

1. TRANSLATE the problem information

  • Given information:
    • Initial amount of water: 300 gallons
    • Drainage rate: 15 gallons per minute
    • Variables: \(\mathrm{w}\) = water remaining (gallons), \(\mathrm{t}\) = time (minutes)

2. INFER the mathematical relationship

  • Since water is being drained (removed), the amount remaining decreases over time
  • This creates a linear relationship where:
    • Starting point (when \(\mathrm{t = 0}\)): \(\mathrm{w = 300}\)
    • Rate of decrease: 15 gallons per minute
  • The equation structure is: \(\mathrm{w = (starting\, amount) - (amount\, drained)}\)

3. Build the equation step by step

  • Amount drained after t minutes = \(\mathrm{15 \times t = 15t}\)
  • Water remaining = Initial amount - Amount drained
  • \(\mathrm{w = 300 - 15t}\)

4. Verify by checking the pattern

  • At \(\mathrm{t = 0}\): \(\mathrm{w = 300 - 15(0) = 300}\) ✓ (matches initial condition)
  • At \(\mathrm{t = 1}\): \(\mathrm{w = 300 - 15(1) = 285}\) ✓ (makes sense: 15 gallons drained)
  • At \(\mathrm{t = 20}\): \(\mathrm{w = 300 - 15(20) = 0}\) ✓ (tank empty after 20 minutes)

Answer: D




Why Students Usually Falter on This Problem


Most Common Error Path:

Weak INFER reasoning: Students confuse "draining" with "filling" and think the water amount increases over time.

They might reason: "Water is being added at 15 gallons per minute, so \(\mathrm{w = 300 + 15t}\)." This fundamental misunderstanding of the situation's direction leads them to select Choice C (\(\mathrm{w = 300 + 15t}\)).


Second Most Common Error:

Poor TRANSLATE execution: Students correctly understand that water decreases but mix up which number represents the constant term versus the coefficient.

They might write something like \(\mathrm{w = 15t - 300}\) or \(\mathrm{w = 285t}\), either by incorrectly placing the 300 or by somehow combining the numbers incorrectly. This confusion about equation structure may lead them to select Choice A (\(\mathrm{w = 285t}\)) or Choice B (\(\mathrm{w = 15t - 300}\)).


The Bottom Line:

This problem tests whether students can correctly model a decreasing linear relationship. The key insight is recognizing that "draining" means subtraction, and the initial amount serves as the starting point from which we subtract the accumulated drainage.

Answer Choices Explained
A

\(\mathrm{w = 285t}\)

B

\(\mathrm{w = 15t - 300}\)

C

\(\mathrm{w = 300 + 15t}\)

D

\(\mathrm{w = 300 - 15t}\)

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