A storage tank initially contains 300 gallons of water. The water is drained from the tank at a constant rate...
GMAT Algebra : (Alg) Questions
A storage tank initially contains 300 gallons of water. The water is drained from the tank at a constant rate of 15 gallons per minute. Which equation represents this situation, where \(\mathrm{w}\) is the amount of water, in gallons, remaining in the tank after \(\mathrm{t}\) minutes?
\(\mathrm{w = 285t}\)
\(\mathrm{w = 15t - 300}\)
\(\mathrm{w = 300 + 15t}\)
\(\mathrm{w = 300 - 15t}\)
1. TRANSLATE the problem information
- Given information:
- Initial amount of water: 300 gallons
- Drainage rate: 15 gallons per minute
- Variables: \(\mathrm{w}\) = water remaining (gallons), \(\mathrm{t}\) = time (minutes)
2. INFER the mathematical relationship
- Since water is being drained (removed), the amount remaining decreases over time
- This creates a linear relationship where:
- Starting point (when \(\mathrm{t = 0}\)): \(\mathrm{w = 300}\)
- Rate of decrease: 15 gallons per minute
- The equation structure is: \(\mathrm{w = (starting\, amount) - (amount\, drained)}\)
3. Build the equation step by step
- Amount drained after t minutes = \(\mathrm{15 \times t = 15t}\)
- Water remaining = Initial amount - Amount drained
- \(\mathrm{w = 300 - 15t}\)
4. Verify by checking the pattern
- At \(\mathrm{t = 0}\): \(\mathrm{w = 300 - 15(0) = 300}\) ✓ (matches initial condition)
- At \(\mathrm{t = 1}\): \(\mathrm{w = 300 - 15(1) = 285}\) ✓ (makes sense: 15 gallons drained)
- At \(\mathrm{t = 20}\): \(\mathrm{w = 300 - 15(20) = 0}\) ✓ (tank empty after 20 minutes)
Answer: D
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak INFER reasoning: Students confuse "draining" with "filling" and think the water amount increases over time.
They might reason: "Water is being added at 15 gallons per minute, so \(\mathrm{w = 300 + 15t}\)." This fundamental misunderstanding of the situation's direction leads them to select Choice C (\(\mathrm{w = 300 + 15t}\)).
Second Most Common Error:
Poor TRANSLATE execution: Students correctly understand that water decreases but mix up which number represents the constant term versus the coefficient.
They might write something like \(\mathrm{w = 15t - 300}\) or \(\mathrm{w = 285t}\), either by incorrectly placing the 300 or by somehow combining the numbers incorrectly. This confusion about equation structure may lead them to select Choice A (\(\mathrm{w = 285t}\)) or Choice B (\(\mathrm{w = 15t - 300}\)).
The Bottom Line:
This problem tests whether students can correctly model a decreasing linear relationship. The key insight is recognizing that "draining" means subtraction, and the initial amount serves as the starting point from which we subtract the accumulated drainage.
\(\mathrm{w = 285t}\)
\(\mathrm{w = 15t - 300}\)
\(\mathrm{w = 300 + 15t}\)
\(\mathrm{w = 300 - 15t}\)