Which of the following systems of linear equations has no solution?
GMAT Algebra : (Alg) Questions
Which of the following systems of linear equations has no solution?
\(\mathrm{y = 6x + 3}\)
\(\mathrm{y = 6x + 9}\)
\(\mathrm{y = 10}\)
\(\mathrm{y = 10x + 10}\)
\(\mathrm{y = 14x + 14}\)
\(\mathrm{y = 10x + 14}\)
\(\mathrm{x = 3}\)
\(\mathrm{y = 10}\)
1. TRANSLATE the key concept
- For a system of linear equations to have no solution, the lines must be:
- Parallel (same slope)
- But distinct (different y-intercepts)
2. TRANSLATE each system to identify slopes and y-intercepts
Choice A: \(\mathrm{y = 6x + 3}\) and \(\mathrm{y = 6x + 9}\)
- \(\mathrm{Slope_1 = 6}\), \(\mathrm{y\text{-}intercept_1 = 3}\)
- \(\mathrm{Slope_2 = 6}\), \(\mathrm{y\text{-}intercept_2 = 9}\)
Choice B: \(\mathrm{y = 10}\) and \(\mathrm{y = 10x + 10}\)
- First equation: horizontal line (\(\mathrm{slope = 0}\), \(\mathrm{y\text{-}intercept = 10}\))
- Second equation: \(\mathrm{slope = 10}\), \(\mathrm{y\text{-}intercept = 10}\)
Choice C: \(\mathrm{y = 14x + 14}\) and \(\mathrm{y = 10x + 14}\)
- \(\mathrm{Slope_1 = 14}\), \(\mathrm{y\text{-}intercept_1 = 14}\)
- \(\mathrm{Slope_2 = 10}\), \(\mathrm{y\text{-}intercept_2 = 14}\)
Choice D: \(\mathrm{x = 3}\) and \(\mathrm{y = 10}\)
- First equation: vertical line
- Second equation: horizontal line
3. INFER which system has no solution
- Choice A: Same slopes (\(\mathrm{6 = 6}\)) ✓, Different y-intercepts (\(\mathrm{3 \neq 9}\)) ✓
→ Parallel but distinct lines → No solution - Choice B: Different slopes (\(\mathrm{0 \neq 10}\)) → Lines intersect → Has solution
- Choice C: Different slopes (\(\mathrm{14 \neq 10}\)) → Lines intersect → Has solution
- Choice D: Vertical and horizontal lines → Always intersect → Has solution
Answer: A
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak INFER skill: Confusing the conditions for no solution by thinking that when two equations have the same y-intercept but different slopes, there's no solution.
Looking at Choice C (\(\mathrm{y = 14x + 14}\) and \(\mathrm{y = 10x + 14}\)), students see both equations have \(\mathrm{y\text{-}intercept = 14}\) and think "they're the same line" or "they don't intersect." However, different slopes actually guarantee the lines will intersect at exactly one point (the y-intercept point in this case).
This may lead them to select Choice C (\(\mathrm{y = 14x + 14}\), \(\mathrm{y = 10x + 14}\)).
Second Most Common Error:
Inadequate TRANSLATE reasoning: Misidentifying what constitutes parallel lines by focusing only on coefficients rather than slopes.
Students might look at Choice A and think "\(\mathrm{6x}\) appears in both equations, but the constants are different, so they must intersect somewhere." They fail to recognize that identical slopes with different y-intercepts create parallel lines that never meet.
This leads to confusion and guessing among the other choices.
The Bottom Line:
This problem tests whether students truly understand the geometric meaning of slope and y-intercept in determining when lines are parallel versus intersecting. The key insight is that parallel lines (same slope) with different starting points (different y-intercepts) can never meet.
\(\mathrm{y = 6x + 3}\)
\(\mathrm{y = 6x + 9}\)
\(\mathrm{y = 10}\)
\(\mathrm{y = 10x + 10}\)
\(\mathrm{y = 14x + 14}\)
\(\mathrm{y = 10x + 14}\)
\(\mathrm{x = 3}\)
\(\mathrm{y = 10}\)