The table gives the number of hours, h, of labor and a plumber's total charge \(\mathrm{f(h)}\), in dollars, for two...
GMAT Algebra : (Alg) Questions
The table gives the number of hours, \(\mathrm{h}\), of labor and a plumber's total charge \(\mathrm{f(h)}\), in dollars, for two different jobs. There is a linear relationship between \(\mathrm{h}\) and \(\mathrm{f(h)}\). Which equation represents this relationship?
| \(\mathrm{h}\) | \(\mathrm{f(h)}\) |
|---|---|
| 1 | 155 |
| 3 | 285 |
\(\mathrm{f(h) = 25h + 130}\)
\(\mathrm{f(h) = 130h + 25}\)
\(\mathrm{f(h) = 65h + 90}\)
\(\mathrm{f(h) = 90h + 65}\)
1. TRANSLATE the problem information
- Given information:
- Two points: \((1, 155)\) and \((3, 285)\)
- Linear relationship between h and f(h)
- Need to find equation in form \(\mathrm{f(h) = mh + b}\)
2. INFER the solution strategy
- Since we have two points on a linear function, we can:
- First find the slope (rate of change)
- Then use either point to find the y-intercept
3. SIMPLIFY to find the slope
- Using slope formula: \(\mathrm{m = \frac{y_2 - y_1}{x_2 - x_1}}\)
- \(\mathrm{m = \frac{285 - 155}{3 - 1}}\)
- \(\mathrm{m = \frac{130}{2}}\)
- \(\mathrm{m = 65}\)
4. SIMPLIFY to find the y-intercept
- Substitute slope and one point into \(\mathrm{f(h) = mh + b}\)
- Using point \((1, 155)\): \(\mathrm{155 = 65(1) + b}\)
- \(\mathrm{155 = 65 + b}\)
- \(\mathrm{b = 90}\)
5. Write the final equation
- \(\mathrm{f(h) = 65h + 90}\)
Answer: C. \(\mathrm{f(h) = 65h + 90}\)
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak SIMPLIFY skill: Students calculate the change in f(h) correctly as \(\mathrm{285 - 155 = 130}\), but forget to divide by the change in h.
They think: "The rate of change is 130" and write \(\mathrm{f(h) = 130h + b}\). Then using point \((1, 155)\): \(\mathrm{155 = 130(1) + b}\), so \(\mathrm{b = 25}\).
This may lead them to select Choice B (\(\mathrm{f(h) = 130h + 25}\))
Second Most Common Error:
Poor SIMPLIFY execution: Students make arithmetic errors when calculating the slope or solving for b, leading to incorrect values that happen to match wrong answer choices.
For example, miscalculating \(\mathrm{130 \div 2}\) or making sign errors when solving \(\mathrm{155 = 65 + b}\).
This may lead them to select Choice A (\(\mathrm{f(h) = 25h + 130}\)) or Choice D (\(\mathrm{f(h) = 90h + 65}\))
The Bottom Line:
This problem tests whether students can systematically apply the two-step process for finding linear equations: calculate slope correctly, then substitute carefully to find the y-intercept. The most dangerous error is treating the numerator of the slope calculation as the final slope value.
\(\mathrm{f(h) = 25h + 130}\)
\(\mathrm{f(h) = 130h + 25}\)
\(\mathrm{f(h) = 65h + 90}\)
\(\mathrm{f(h) = 90h + 65}\)