The table shows four values of x and their corresponding values of \(\mathrm{f(x)}\). There is a linear relationship between x...
GMAT Algebra : (Alg) Questions
The table shows four values of \(\mathrm{x}\) and their corresponding values of \(\mathrm{f(x)}\). There is a linear relationship between \(\mathrm{x}\) and \(\mathrm{f(x)}\) that is defined by the equation \(\mathrm{f(x) = mx - 28}\), where \(\mathrm{m}\) is a constant. What is the value of \(\mathrm{m}\)?
| \(\mathrm{x}\) | \(\mathrm{f(x)}\) |
|---|---|
| 10 | 82 |
| 15 | 137 |
| 20 | 192 |
| 25 | 247 |
1. TRANSLATE the problem information
- Given information:
- Linear equation form: \(\mathrm{f(x) = mx - 28}\)
- Table of coordinate pairs showing x and f(x) values
- Need to find the constant m
- What this tells us: We can substitute any coordinate pair from the table into the equation to create a solvable equation for m
2. TRANSLATE coordinate data into equation
- Choose any coordinate pair from the table (they should all work)
- Using \(\mathrm{(10, 82)}\): When \(\mathrm{x = 10}\), \(\mathrm{f(x) = 82}\)
- Substitute into \(\mathrm{f(x) = mx - 28}\):
\(\mathrm{82 = m(10) - 28}\)
3. SIMPLIFY to solve for m
- Start with: \(\mathrm{82 = 10m - 28}\)
- Add 28 to both sides: \(\mathrm{82 + 28 = 10m}\)
- Calculate: \(\mathrm{110 = 10m}\)
- Divide by 10: \(\mathrm{m = 11}\)
4. Verify your answer (optional but recommended)
- Test with another point like \(\mathrm{(15, 137)}\):
- \(\mathrm{f(15) = 11(15) - 28}\)
\(\mathrm{= 165 - 28}\)
\(\mathrm{= 137}\) ✓
Answer: 11
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak TRANSLATE reasoning: Students may not understand how to connect the table data to the equation form. They might think they need to use all four points simultaneously or try to find a pattern in the table without using the given equation structure.
This leads to confusion and guessing rather than systematic substitution.
Second Most Common Error:
Poor SIMPLIFY execution: Students make arithmetic errors in the algebraic steps, such as:
- Forgetting to add 28 to both sides correctly
- Making calculation errors like 82 + 28 = 100 instead of 110
- Division errors when solving 110 = 10m
This may lead them to select incorrect numerical answers or abandon the solution process.
The Bottom Line:
The key insight is recognizing that each coordinate pair gives you a complete equation to solve - you don't need complex analysis, just careful substitution and algebra.