QUESTION STEM:A taxi fare is modeled by \(\mathrm{T(d) = ad + c}\), where d is the distance in miles and...
GMAT Algebra : (Alg) Questions
- A taxi fare is modeled by \(\mathrm{T(d) = ad + c}\), where \(\mathrm{d}\) is the distance in miles and \(\mathrm{a}\) and \(\mathrm{c}\) are constants.
- A 2-mile trip costs $13, and a 5-mile trip costs $22.
- What is the value of \(\mathrm{a}\)?
Answer Format Instructions: Enter your answer as an integer.
1. TRANSLATE the problem information
- Given information:
- Taxi fare function: \(\mathrm{T(d) = a \cdot d + c}\)
- 2-mile trip costs \(\$13\)
- 5-mile trip costs \(\$22\)
- Need to find: value of a
2. TRANSLATE the scenarios into equations
- Substitute the given trip data into the function:
- For 2 miles: \(\mathrm{T(2) = 2a + c = 13}\)
- For 5 miles: \(\mathrm{T(5) = 5a + c = 22}\)
- This gives us a system of two equations with two unknowns (a and c)
3. INFER the best solution strategy
- We have:
- \(\mathrm{2a + c = 13}\)
- \(\mathrm{5a + c = 22}\)
- Since both equations have the same "+c" term, elimination by subtraction will directly solve for a
- This avoids having to find c first
4. SIMPLIFY by eliminating c
- Subtract the first equation from the second:
\(\mathrm{(5a + c) - (2a + c) = 22 - 13}\) - The c terms cancel out:
\(\mathrm{5a + c - 2a - c = 9}\)
\(\mathrm{3a = 9}\) - Divide both sides by 3:
\(\mathrm{a = 3}\)
5. Verify the solution (optional but recommended)
- If \(\mathrm{a = 3}\), then from the first equation: \(\mathrm{c = 13 - 2(3) = 7}\)
- Check with second equation: \(\mathrm{5(3) + 7 = 22}\) ✓
Answer: 3
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak TRANSLATE reasoning: Students may try to work with just one equation instead of recognizing they need both pieces of information to create a solvable system.
They might use only \(\mathrm{T(2) = 13}\) and think they can somehow find a directly, not realizing they have two unknowns (a and c) but only one equation. This leads to confusion and guessing.
Second Most Common Error:
Poor INFER strategy: Students correctly set up the system but choose substitution instead of elimination, making the algebra more complex and error-prone.
They might solve \(\mathrm{2a + c = 13}\) for c (getting \(\mathrm{c = 13 - 2a}\)), then substitute into the second equation, leading to more chances for arithmetic mistakes during the SIMPLIFY phase.
The Bottom Line:
This problem tests whether students can efficiently translate real-world linear relationships into mathematical systems and choose the most direct solution path. The key insight is recognizing that elimination immediately isolates the target variable.