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At a fundraiser, the ticket price, in dollars, is set to be x increased by 20% of x, and the...

GMAT Advanced Math : (Adv_Math) Questions

Source: Prism
Advanced Math
Nonlinear functions
EASY
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Notes
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At a fundraiser, the ticket price, in dollars, is set to be \(\mathrm{x}\) increased by 20% of \(\mathrm{x}\), and the number of tickets sold is modeled by \(\mathrm{150 - 5x}\). The revenue \(\mathrm{R(x)}\) equals price times number of tickets. What is the value of \(\mathrm{R(10)}\)?

A

1,000

B

1,200

C

1,750

D

1,800

Solution

1. TRANSLATE the problem information

  • Given information:
    • Ticket price = x increased by 20% of x
    • Number of tickets sold = \(\mathrm{150 - 5x}\)
    • Revenue \(\mathrm{R(x) = price \times number~of~tickets}\)
    • Need to find \(\mathrm{R(10)}\)
  • What this tells us:
    • Price = \(\mathrm{x + 0.20x = 1.20x}\) dollars
    • Quantity = \(\mathrm{150 - 5x}\) tickets

2. INFER what we need to do

  • To find \(\mathrm{R(10)}\), we need to substitute \(\mathrm{x = 10}\) into our revenue formula
  • This means calculating both the price and quantity when \(\mathrm{x = 10}\)
  • Then multiply them together for the revenue

3. SIMPLIFY by substituting x = 10

  • Price when \(\mathrm{x = 10}\): \(\mathrm{1.20(10) = 12}\) dollars
  • Quantity when \(\mathrm{x = 10}\): \(\mathrm{150 - 5(10) = 150 - 50 = 100}\) tickets
  • Revenue: \(\mathrm{R(10) = 12 \times 100 = 1,200}\) dollars

Answer: B. 1,200




Why Students Usually Falter on This Problem


Most Common Error Path:

Weak TRANSLATE skill: Students may interpret "x increased by 20% of x" incorrectly as \(\mathrm{x + 20}\) instead of \(\mathrm{x + 0.20x}\).

If they use price = \(\mathrm{x + 20}\), then when \(\mathrm{x = 10}\):

  • Price = \(\mathrm{10 + 20 = 30}\) dollars
  • Quantity = \(\mathrm{150 - 5(10) = 100}\) tickets
  • Revenue = \(\mathrm{30 \times 100 = 3,000}\) dollars

This doesn't match any answer choice, leading to confusion and guessing.


Second Most Common Error:

Poor SIMPLIFY execution: Students correctly set up \(\mathrm{1.20x}\) but make arithmetic errors in the final calculation.

For example, they might calculate \(\mathrm{1.20 \times 10 = 10.20}\) instead of 12, leading to:

  • Revenue = \(\mathrm{10.20 \times 100 = 1,020}\) dollars

This also doesn't match any answer choice, causing them to second-guess their approach.


The Bottom Line:

This problem tests your ability to translate percentage language into mathematical expressions. The key insight is recognizing that "increased by 20%" means multiplying by 1.20, not adding 20.

Answer Choices Explained
A

1,000

B

1,200

C

1,750

D

1,800

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