Triangle A has a base of 8 centimeters and a height of 9 centimeters. Triangle B has the same height...
GMAT Geometry & Trigonometry : (Geo_Trig) Questions
Triangle A has a base of \(\mathrm{8}\) centimeters and a height of \(\mathrm{9}\) centimeters. Triangle B has the same height as triangle A, but its area is \(\mathrm{\frac{3}{2}}\) times the area of triangle A. What is the length, in centimeters, of the base of triangle B?
- 6
- 12
- 16
- 18
6
12
16
18
1. TRANSLATE the problem information
- Given information:
- Triangle A: base = 8 cm, height = 9 cm
- Triangle B: same height as A (9 cm), area = \(\frac{3}{2}\) × area of A
- Find: base of triangle B
2. SIMPLIFY to find triangle A's area
- Use the triangle area formula: \(\mathrm{Area} = \frac{1}{2} \times \mathrm{base} \times \mathrm{height}\)
- Area of triangle A = \(\frac{1}{2} \times 8 \times 9 = 36\) square centimeters
3. TRANSLATE the area relationship for triangle B
- Area of triangle B = \(\frac{3}{2} \times \mathrm{area\ of\ triangle\ A}\)
- Area of triangle B = \(\frac{3}{2} \times 36 = 54\) square centimeters
4. SIMPLIFY to find triangle B's base
- Use the area formula with triangle B's known area and height:
- \(54 = \frac{1}{2} \times \mathrm{base} \times 9\)
- \(54 = \frac{9}{2} \times \mathrm{base}\)
- \(\mathrm{base} = 54 \times \frac{2}{9} = 12\) centimeters
Answer: B (12)
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak TRANSLATE skill: Students misinterpret "3/2 times the area of triangle A" and think triangle B's base should be 3/2 times triangle A's base, completely bypassing the area calculation step.
They might calculate: base of B = \(\frac{3}{2} \times 8 = 12\), getting the right answer by luck, or they might get confused about what measurement is being scaled and make errors like base = \(8 \times \frac{2}{3} = \frac{16}{3}\), leading to confusion and guessing.
Second Most Common Error:
Inadequate SIMPLIFY execution: Students correctly set up the final equation \(54 = \frac{9}{2} \times \mathrm{base}\) but make arithmetic errors when solving for the base, such as incorrectly calculating \(54 \div \frac{9}{2}\) or forgetting to multiply by the reciprocal.
This leads to wrong numerical answers that might make them select Choice A (6) if they divided incorrectly, or Choice C (16) if they made reciprocal errors.
The Bottom Line:
This problem tests whether students can work systematically through a multi-step area relationship rather than jumping to conclusions about which measurements are directly proportional.
6
12
16
18