In the xy-plane, a circle has equation x^2 + y^2 - 14x + 10y = k, where k is a...
GMAT Geometry & Trigonometry : (Geo_Trig) Questions
In the xy-plane, a circle has equation \(\mathrm{x^2 + y^2 - 14x + 10y = k}\), where \(\mathrm{k}\) is a constant. The point \(\mathrm{(3, -5)}\) lies on the circle. What is the length of the circle's radius?
- 2
- 4
- 6
- 8
- 16
1. TRANSLATE the given information
- Given information:
- Circle equation: \(\mathrm{x^2 + y^2 - 14x + 10y = k}\)
- Point (3, -5) lies on the circle
- What this tells us: Since the point lies on the circle, its coordinates must satisfy the equation
2. INFER the solution strategy
- We need the radius, which requires the standard form \(\mathrm{(x - h)^2 + (y - k)^2 = r^2}\)
- First find k using the given point, then complete the square
3. TRANSLATE and substitute to find k
- Substitute \(\mathrm{x = 3, y = -5}\) into the equation:
\(\mathrm{3^2 + (-5)^2 - 14(3) + 10(-5) = k}\) - Calculate:
\(\mathrm{9 + 25 - 42 - 50 = k}\) - Therefore:
\(\mathrm{k = -58}\)
4. SIMPLIFY by completing the square
- Start with: \(\mathrm{x^2 + y^2 - 14x + 10y = -58}\)
- Group terms: \(\mathrm{(x^2 - 14x) + (y^2 + 10y) = -58}\)
- Complete the square for x: \(\mathrm{x^2 - 14x = (x - 7)^2 - 49}\)
- Complete the square for y: \(\mathrm{y^2 + 10y = (y + 5)^2 - 25}\)
- Substitute back: \(\mathrm{(x - 7)^2 - 49 + (y + 5)^2 - 25 = -58}\)
5. SIMPLIFY to standard form
- Combine constants:
\(\mathrm{(x - 7)^2 + (y + 5)^2 = -58 + 49 + 25}\) - Final form:
\(\mathrm{(x - 7)^2 + (y + 5)^2 = 16}\)
6. INFER the radius value
- Since the standard form is \(\mathrm{(x - h)^2 + (y - k)^2 = r^2}\), we have \(\mathrm{r^2 = 16}\)
- Therefore \(\mathrm{r = 4}\)
Answer: B) 4
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak INFER skill: Students recognize they need to complete the square but forget that the final result gives \(\mathrm{r^2}\), not r directly.
After correctly completing the square to get \(\mathrm{(x - 7)^2 + (y + 5)^2 = 16}\), they see "16" and immediately think the radius is 16. They fail to recognize that this coefficient represents \(\mathrm{r^2}\), requiring them to take the square root for the actual radius.
This may lead them to select Choice E (16).
Second Most Common Error:
Poor TRANSLATE reasoning: Students substitute the point incorrectly or make arithmetic errors when calculating k.
For example, they might write \(\mathrm{(-5)^2}\) as -25 instead of +25, or make sign errors when substituting into \(\mathrm{-14x + 10y}\). This leads to an incorrect value of k, which propagates through the entire solution and results in a wrong radius calculation.
This leads to confusion and guessing among the remaining choices.
The Bottom Line:
This problem requires careful attention to the distinction between \(\mathrm{r^2}\) and r. Many students complete the algebraic work correctly but miss the final conceptual step of taking the square root.