Triangle PQR has vertices \(\mathrm{P(1, 0)}\), \(\mathrm{Q(0, 0)}\), and \(\mathrm{R(0, 1)}\) in the coordinate plane. The positive measure of angle...
GMAT Geometry & Trigonometry : (Geo_Trig) Questions
Triangle \(\mathrm{PQR}\) has vertices \(\mathrm{P(1, 0)}\), \(\mathrm{Q(0, 0)}\), and \(\mathrm{R(0, 1)}\) in the coordinate plane. The positive measure of angle \(\mathrm{PQR}\) includes the angle from ray \(\mathrm{QP}\) to ray \(\mathrm{QR}\) measured counterclockwise. Which of the following could be this positive angle measure, in radians?
\(\frac{25\pi}{2}\)
\(\frac{27\pi}{2}\)
\(24\pi\)
\(\frac{23\pi}{2}\)
\(26\pi\)
1. TRANSLATE the problem information
- Given information:
- Triangle PQR with \(\mathrm{Q(0, 0)}\), \(\mathrm{P(1, 0)}\), \(\mathrm{R(0, 1)}\)
- Need positive measure of angle PQR from ray QP to ray QR, counterclockwise
- What this tells us:
- Q is at the origin, so we're measuring from origin
- Ray QP goes to \(\mathrm{(1, 0)}\) = along positive x-axis
- Ray QR goes to \(\mathrm{(0, 1)}\) = along positive y-axis
2. VISUALIZE the angle setup
- INFER the basic angle measurement:
- From positive x-axis to positive y-axis, counterclockwise = \(\frac{\pi}{2}\) radians
- This is the fundamental angle we're measuring
3. INFER the complete solution approach
- Key insight: "Positive angle measure" means we can include full rotations
- General form: \(\frac{\pi}{2} + 2\pi k\) where k is any non-negative integer
- Need to check which answer choice fits this pattern
4. SIMPLIFY each answer choice
- Check if each equals \(\frac{\pi}{2} + 2\pi k\) for some integer \(\mathrm{k \geq 0}\):
Choice A:
\(\frac{25\pi}{2} = \frac{\pi}{2} + \frac{24\pi}{2}\)
\(= \frac{\pi}{2} + 12\pi\)
\(= \frac{\pi}{2} + 6(2\pi)\)
→ \(\mathrm{k = 6}\) ✓ (integer)
Choice B:
\(\frac{27\pi}{2} = \frac{\pi}{2} + \frac{26\pi}{2}\)
\(= \frac{\pi}{2} + 13\pi\)
→ \(13\pi = 2\pi k\)
→ \(\mathrm{k = 6.5}\) ✗ (not integer)
Choice C:
\(24\pi = \frac{\pi}{2} + 2\pi k\)
→ \(2\pi k = 24\pi - \frac{\pi}{2}\)
\(= \frac{48\pi - \pi}{2}\)
\(= \frac{47\pi}{2}\)
→ \(\mathrm{k = \frac{47}{4} = 11.75}\) ✗ (not integer)
Choice D:
\(\frac{23\pi}{2} = \frac{\pi}{2} + \frac{22\pi}{2}\)
\(= \frac{\pi}{2} + 11\pi\)
→ \(11\pi = 2\pi k\)
→ \(\mathrm{k = 5.5}\) ✗ (not integer)
Choice E:
\(26\pi = \frac{\pi}{2} + 2\pi k\)
→ \(\mathrm{k = \frac{52\pi - \pi}{4\pi}}\)
\(= \frac{51}{4}\)
\(= 12.75\) ✗ (not integer)
5. APPLY CONSTRAINTS to select final answer
- Only choice A gives an integer value for k
- \(\mathrm{k = 6}\) means 6 full counterclockwise rotations plus \(\frac{\pi}{2}\)
Answer: A \(\left(\frac{25\pi}{2}\right)\)
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak INFER skill: Students find the basic angle \(\frac{\pi}{2}\) correctly but don't recognize that "positive angle measure" can include multiple rotations. They look for answer choices close to \(\frac{\pi}{2} \approx 1.57\), not realizing the problem allows for coterminal angles.
This leads to confusion since none of the choices are close to \(\frac{\pi}{2}\), causing them to guess or abandon the systematic approach.
Second Most Common Error:
Poor SIMPLIFY execution: Students understand the coterminal angle concept but make algebraic errors when checking if k is an integer. They might incorrectly conclude that other choices work, particularly with decimal/fraction arithmetic involving π.
This may lead them to select Choice B \(\left(\frac{27\pi}{2}\right)\) or Choice D \(\left(\frac{23\pi}{2}\right)\) due to computational mistakes.
The Bottom Line:
This problem tests whether students can bridge basic angle measurement with the concept of coterminal angles, requiring both geometric visualization and algebraic verification skills.
\(\frac{25\pi}{2}\)
\(\frac{27\pi}{2}\)
\(24\pi\)
\(\frac{23\pi}{2}\)
\(26\pi\)