A structural engineer designs triangular support frames where stability requirements dictate that the sum of any two beam lengths must...
GMAT Algebra : (Alg) Questions
A structural engineer designs triangular support frames where stability requirements dictate that the sum of any two beam lengths must exceed the third beam length by at least 4 feet. If a triangular frame has beam lengths of 5 feet and 14 feet, which inequality represents the possible lengths, \(\mathrm{b}\), in feet, for the third beam?
\(\mathrm{b \leq 15}\)
\(\mathrm{b \geq 13}\)
\(\mathrm{13 \leq b \leq 15}\)
\(\mathrm{9 \leq b \leq 19}\)
\(\mathrm{5 \leq b \leq 14}\)
1. TRANSLATE the problem information
- Given information:
- Two beam lengths: 5 feet and 14 feet
- Third beam length: b feet (unknown)
- Constraint: sum of any two beams ≥ third beam + 4 feet
- What this tells us: We need to apply this constraint in all possible combinations of beams
2. INFER the approach
- Since we have three beams total, there are three ways to pick "any two beams"
- We must write three separate inequalities, one for each pair
- All three inequalities must be true simultaneously
3. TRANSLATE each constraint into mathematical form
- Pair 1: (5 + 14) vs. b → \(5 + 14 \geq b + 4\)
- Pair 2: (5 + b) vs. 14 → \(5 + b \geq 14 + 4\)
- Pair 3: (14 + b) vs. 5 → \(14 + b \geq 5 + 4\)
4. SIMPLIFY each inequality
- From constraint 1: \(19 \geq b + 4\) → \(b \leq 15\)
- From constraint 2: \(5 + b \geq 18\) → \(b \geq 13\)
- From constraint 3: \(14 + b \geq 9\) → \(b \geq -5\)
5. APPLY CONSTRAINTS to find the final answer
- The third constraint (\(b \geq -5\)) is automatically satisfied since beam lengths are positive
- We need both \(b \leq 15\) AND \(b \geq 13\)
- Combined: \(13 \leq b \leq 15\)
Answer: C
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak INFER skill: Students apply the constraint in only one direction, typically just ensuring \(5 + 14 \geq b + 4\), which gives \(b \leq 15\). They miss that the constraint must work in all three directions and forget to check what happens when b is one of the "two beams" being added together.
This incomplete analysis may lead them to select Choice A (\(b \leq 15\)).
Second Most Common Error:
Poor TRANSLATE reasoning: Students confuse this with the standard triangle inequality (where the sum just needs to be greater than, not greater than plus 4). They set up \(5 + 14 \gt b\), \(5 + b \gt 14\), and \(14 + b \gt 5\), getting \(b \lt 19\), \(b \gt 9\), and \(b \gt -9\), leading to \(9 \lt b \lt 19\).
This may lead them to select Choice D (\(9 \leq b \leq 19\)).
The Bottom Line:
This problem requires careful attention to the modified constraint (adding 4 feet) and systematic application in all directions. Students who rush through the setup or apply constraints incompletely will miss the correct range.
\(\mathrm{b \leq 15}\)
\(\mathrm{b \geq 13}\)
\(\mathrm{13 \leq b \leq 15}\)
\(\mathrm{9 \leq b \leq 19}\)
\(\mathrm{5 \leq b \leq 14}\)