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Two rectangular posters each have height h inches. The widths of the posters are 2h - 3 inches and 5h...

GMAT Advanced Math : (Adv_Math) Questions

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Two rectangular posters each have height \(\mathrm{h}\) inches. The widths of the posters are \(2\mathrm{h} - 3\) inches and \(5\mathrm{h} + 1\) inches, respectively. What is the total area, in square inches, of the two posters in terms of \(\mathrm{h}\)?

A
\(7\mathrm{h}^2 - 2\mathrm{h}\)
B
\(7\mathrm{h}^2 + 2\mathrm{h}\)
C
\(7\mathrm{h}\)
D
\(7\mathrm{h}^2\)
Solution

1. TRANSLATE the problem information

  • Given information:
    • Two rectangular posters, both with height \(\mathrm{h}\) inches
    • First poster width: \(\mathrm{2h - 3}\) inches
    • Second poster width: \(\mathrm{5h + 1}\) inches
    • Need: Total area in square inches

2. INFER the solution approach

  • Since we need total area, we'll find each poster's area separately then add them
  • Use the rectangle area formula: \(\mathrm{Area = height \times width}\)

3. SIMPLIFY to find each poster's area

For the first poster:

\(\mathrm{Area_1 = h \times (2h - 3)}\)

\(\mathrm{= h(2h - 3)}\)

\(\mathrm{= 2h^2 - 3h}\)

For the second poster:

\(\mathrm{Area_2 = h \times (5h + 1)}\)

\(\mathrm{= h(5h + 1)}\)

\(\mathrm{= 5h^2 + h}\)


4. SIMPLIFY to find the total area

\(\mathrm{Total\:area = Area_1 + Area_2}\)

\(\mathrm{= (2h^2 - 3h) + (5h^2 + h)}\)

\(\mathrm{= 2h^2 - 3h + 5h^2 + h}\)

\(\mathrm{= 7h^2 - 2h}\)

Answer: A (\(\mathrm{7h^2 - 2h}\))




Why Students Usually Falter on This Problem


Most Common Error Path:

Weak SIMPLIFY execution: Students correctly set up both areas but make sign errors when combining like terms. They might calculate \(\mathrm{-3h + h = +2h}\) instead of \(\mathrm{-2h}\), getting \(\mathrm{7h^2 + 2h}\) as their final answer.

This leads them to select Choice B (\(\mathrm{7h^2 + 2h}\)).


Second Most Common Error:

Incomplete SIMPLIFY process: Students correctly find the individual areas but forget to combine the constant terms (the \(\mathrm{h}\) terms), only adding the \(\mathrm{h^2}\) coefficients. They might write \(\mathrm{2h^2 + 5h^2 = 7h^2}\) and stop there.

This causes them to select Choice D (\(\mathrm{7h^2}\)).


The Bottom Line:

This problem tests whether students can systematically work through multi-step algebraic manipulation while keeping track of signs and like terms. The key challenge is maintaining accuracy through the distribution and combining steps rather than rushing to a quick answer.

Answer Choices Explained
A
\(7\mathrm{h}^2 - 2\mathrm{h}\)
B
\(7\mathrm{h}^2 + 2\mathrm{h}\)
C
\(7\mathrm{h}\)
D
\(7\mathrm{h}^2\)
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