If u - 3 = 6/(t - 2), what is t in terms of u?
GMAT Advanced Math : (Adv_Math) Questions
If \(\mathrm{u - 3 = \frac{6}{t - 2}}\), what is t in terms of u?
\(\mathrm{t = \frac{1}{u}}\)
\(\mathrm{t = \frac{2u + 9}{u}}\)
\(\mathrm{t = \frac{1}{u - 3}}\)
\(\mathrm{t = \frac{2u}{u - 3}}\)
1. TRANSLATE the problem information
- Given equation: \(\mathrm{u - 3 = \frac{6}{t - 2}}\)
- Goal: Express t in terms of u
2. INFER the most effective approach
- The fraction on the right side makes this equation complex to work with
- Strategy: Eliminate the fraction by multiplying both sides by \(\mathrm{(t - 2)}\)
- This will give us a simpler equation to manipulate
3. SIMPLIFY by eliminating the fraction
- Multiply both sides by \(\mathrm{(t - 2)}\):
\(\mathrm{(t - 2)(u - 3) = 6}\)
4. SIMPLIFY by expanding the left side
- Use distributive property: \(\mathrm{(t - 2)(u - 3) = tu - 3t - 2u + 6}\)
- So: \(\mathrm{tu - 3t - 2u + 6 = 6}\)
5. SIMPLIFY by collecting like terms
- Subtract 6 from both sides: \(\mathrm{tu - 3t - 2u = 0}\)
- Rearrange to group t terms: \(\mathrm{t(u - 3) - 2u = 0}\)
6. SIMPLIFY to isolate t
- Add 2u to both sides: \(\mathrm{t(u - 3) = 2u}\)
- Divide both sides by \(\mathrm{(u - 3)}\): \(\mathrm{t = \frac{2u}{u - 3}}\)
Answer: D. \(\mathrm{t = \frac{2u}{u - 3}}\)
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak SIMPLIFY execution: Students make sign errors when expanding \(\mathrm{(t - 2)(u - 3)}\) or when rearranging terms. For example, they might get the distribution wrong and write \(\mathrm{tu - 3t + 2u - 6}\) instead of \(\mathrm{tu - 3t - 2u + 6}\), leading to incorrect intermediate steps and ultimately a wrong final answer.
This may lead them to select Choice B \(\mathrm{\left(\frac{2u + 9}{u}\right)}\) or cause confusion and guessing.
Second Most Common Error:
Incomplete INFER reasoning: Students recognize they need to eliminate the fraction but don't complete the full solution process. They might correctly get to \(\mathrm{t - 2 = \frac{6}{u - 3}}\) but then stop or make errors in the final steps of combining fractions.
This may lead them to select Choice C \(\mathrm{\left(\frac{1}{u - 3}\right)}\) after getting confused about how to finish.
The Bottom Line:
This problem requires sustained algebraic manipulation through multiple steps. Success depends on methodical execution of distributive property, careful sign tracking, and persistence through the complete solution process.
\(\mathrm{t = \frac{1}{u}}\)
\(\mathrm{t = \frac{2u + 9}{u}}\)
\(\mathrm{t = \frac{1}{u - 3}}\)
\(\mathrm{t = \frac{2u}{u - 3}}\)