The volume of a right rectangular prism is 119 cubic centimeters. The area of the base of the prism is...
GMAT Geometry & Trigonometry : (Geo_Trig) Questions
The volume of a right rectangular prism is \(119\) cubic centimeters. The area of the base of the prism is \(17\) square centimeters. What is the height, in centimeters, of the prism?
6
7
8
14
17
1. TRANSLATE the problem information
- Given information:
- \(\mathrm{Volume = 119\text{ cubic centimeters}}\)
- \(\mathrm{Base\text{ }Area = 17\text{ square centimeters}}\)
- Need to find: height of the prism
2. INFER the appropriate formula and strategy
- For a right rectangular prism: \(\mathrm{Volume = Base\text{ }Area \times Height}\)
- Since we have volume and base area, we can solve for height
- Strategy: Rearrange the formula to isolate height
3. SIMPLIFY by rearranging and calculating
- Start with: \(\mathrm{119 = 17 \times Height}\)
- Divide both sides by 17: \(\mathrm{Height = 119 \div 17}\)
- Calculate: \(\mathrm{Height = 7\text{ centimeters}}\)
4. Verify the answer
- Check: \(\mathrm{17 \times 7 = 119}\) ✓
Answer: B) 7
Why Students Usually Falter on This Problem
Most Common Error Path:
Conceptual confusion about volume formulas: Students might try to use \(\mathrm{V = l \times w \times h}\) instead of recognizing that the base area is already provided as one combined measurement.
They might think: "I need length, width, and height, but I only have volume and one area measurement." This leads to confusion about what information is actually available and causes them to get stuck or guess randomly.
Second Most Common Error:
Weak SIMPLIFY execution: Students make arithmetic errors when dividing 119 by 17, potentially calculating \(\mathrm{119 \div 17}\) incorrectly.
Common miscalculations might give results like 6, 8, or other values from the answer choices. This may lead them to select Choice A (6) or Choice C (8) based on their incorrect arithmetic.
The Bottom Line:
This problem tests whether students can recognize when they have sufficient information in a different form than expected (base area instead of separate length and width) and apply the volume formula correctly.
6
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8
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17