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\(\mathrm{V(t) = 25,000(1.04)^t}\) The function V defined above can be used to model the value of a piece of industrial...

GMAT Advanced Math : (Adv_Math) Questions

Source: Prism
Advanced Math
Nonlinear functions
MEDIUM
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\(\mathrm{V(t) = 25,000(1.04)^t}\)

The function V defined above can be used to model the value of a piece of industrial equipment, in dollars, t half-year periods after it was purchased. Which of the following is the best interpretation of the model?

A

The value of the equipment increases by a constant amount of \(\$1,000\) every 6 months.

B

The value of the equipment increases by \(4\%\) each year.

C

The value of the equipment increases by \(8\%\) each year.

D

The value of the equipment increases by \(4\%\) every 6 months.

Solution

1. TRANSLATE the model components

  • Given: \(\mathrm{V(t) = 25,000(1.04)^t}\)
  • This follows exponential form: \(\mathrm{f(x) = A(1+r)^x}\)
  • Key detail: t represents "half-year periods" (6-month intervals)

2. INFER what each component represents

  • \(\mathrm{A = 25,000}\) is the initial value (purchase price)
  • \(\mathrm{Base = 1.04 = 1 + 0.04}\), so growth rate \(\mathrm{r = 0.04 = 4\%}\)
  • Since t counts half-year periods, the 4% applies every 6 months

3. INFER the correct interpretation

  • For each unit increase in t (each 6-month period), value multiplies by 1.04
  • This means 4% growth every 6 months
  • This is exponential growth, not linear growth

4. Eliminate incorrect choices

  • (A): Describes linear growth ($1,000 constant), but this is exponential
  • (B): Claims 4% per year, but t measures half-years, not years
  • (C): Assumes 8% annual = 2 × 4% half-year, ignoring compounding

Answer: D




Why Students Usually Falter on This Problem

Most Common Error Path:

Weak INFER skill: Students don't carefully connect the time period to the growth rate. They see "4%" and "equipment value" and jump to annual growth without noticing that t represents half-year periods.

This leads them to select Choice B (4% each year) because they recognize the 4% rate but miss the crucial time scale detail.

Second Most Common Error:

Conceptual confusion about compound growth: Students think that if equipment grows 4% every 6 months, then annual growth is simply 4% × 2 = 8%. They don't realize that compound growth means the second half-year's 4% applies to an already-increased value.

This may lead them to select Choice C (8% each year).

The Bottom Line:

This problem tests whether students can connect all parts of an exponential model - not just identifying the growth rate, but understanding what time period that rate applies to. The key insight is that the variable in the exponent defines your time scale.

Answer Choices Explained
A

The value of the equipment increases by a constant amount of \(\$1,000\) every 6 months.

B

The value of the equipment increases by \(4\%\) each year.

C

The value of the equipment increases by \(8\%\) each year.

D

The value of the equipment increases by \(4\%\) every 6 months.

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