A water tank is drained at a constant rate. After 2 hours, the tank contains 680 liters of water, and...
GMAT Algebra : (Alg) Questions
A water tank is drained at a constant rate. After 2 hours, the tank contains 680 liters of water, and after 5 hours, it contains 500 liters. The amount of water remaining, \(\mathrm{W(t)}\), in liters after \(\mathrm{t}\) hours can be modeled by a linear function \(\mathrm{W(t) = mt + b}\), where \(\mathrm{m}\) and \(\mathrm{b}\) are constants. What is the value of \(\mathrm{b}\)?
1. TRANSLATE the problem information
- Given information:
- Tank drains at constant rate → linear function \(\mathrm{W(t) = mt + b}\)
- After 2 hours: 680 liters → point \(\mathrm{(2, 680)}\)
- After 5 hours: 500 liters → point \(\mathrm{(5, 500)}\)
- What this tells us: We have two points on a line and need to find the y-intercept b
2. INFER the solution strategy
- Since we have two points and need to find b in \(\mathrm{W(t) = mt + b}\), we must:
- First find the slope m using the two points
- Then substitute one point into \(\mathrm{W(t) = mt + b}\) to solve for b
3. SIMPLIFY to find the slope
- Using slope formula: \(\mathrm{m = \frac{y_2 - y_1}{x_2 - x_1}}\)
- \(\mathrm{m = \frac{500 - 680}{5 - 2}}\)
\(\mathrm{= \frac{-180}{3}}\)
\(\mathrm{= -60}\) - So our function is \(\mathrm{W(t) = -60t + b}\)
4. SIMPLIFY to find b using point substitution
- Using point \(\mathrm{(2, 680)}\): \(\mathrm{680 = -60(2) + b}\)
- \(\mathrm{680 = -120 + b}\)
- \(\mathrm{b = 680 + 120 = 800}\)
5. Verify with the second point
- \(\mathrm{W(5) = -60(5) + 800}\)
\(\mathrm{= -300 + 800}\)
\(\mathrm{= 500}\) ✓
Answer: (E) 800
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak TRANSLATE reasoning: Students might confuse which variable represents what, or misinterpret the given information as something other than coordinate points.
For example, they might think b should equal one of the given water amounts (680 or 500) without understanding that b represents the y-intercept (initial amount when \(\mathrm{t = 0}\)). This could lead them to select Choice (A) (500) or Choice (C) (680).
Second Most Common Error:
Poor SIMPLIFY execution: Students correctly understand the approach but make arithmetic errors when calculating the slope or solving for b.
A common mistake is getting the slope calculation wrong (perhaps computing \(\mathrm{180/3 = 60}\) instead of \(\mathrm{-180/3 = -60}\)) or making sign errors during substitution. This leads to an incorrect value of b and may cause them to select Choice (D) (740) or get confused and guess.
The Bottom Line:
This problem tests whether students can work systematically with linear functions from real-world contexts, requiring careful translation of word problems into mathematical relationships and methodical algebraic manipulation.