A water tank initially contains 40 gallons of water. Water drains from the tank at a constant rate of 4...
GMAT Algebra : (Alg) Questions
A water tank initially contains \(\mathrm{40}\) gallons of water. Water drains from the tank at a constant rate of \(\mathrm{4}\) gallons per hour. Which table gives three values of \(\mathrm{t}\) (time in hours) and the corresponding amount of water \(\mathrm{W}\) (in gallons) remaining in the tank?
| \(\mathrm{t}\) | \(\mathrm{W}\) |
|---|---|
| 0 | 0 |
| 1 | 4 |
| 2 | 8 |
| \(\mathrm{t}\) | \(\mathrm{W}\) |
|---|---|
| 0 | 40 |
| 1 | 44 |
| 2 | 48 |
| \(\mathrm{t}\) | \(\mathrm{W}\) |
|---|---|
| 0 | 40 |
| 1 | 36 |
| 2 | 32 |
| \(\mathrm{t}\) | \(\mathrm{W}\) |
|---|---|
| 0 | 0 |
| 1 | -4 |
| 2 | -8 |
1. TRANSLATE the problem information
- Given information:
- Initial amount: 40 gallons
- Drainage rate: 4 gallons per hour (constant)
- Need to find: Water remaining W at different times t
2. INFER the mathematical relationship
- Since water drains at a constant rate, this creates a linear relationship
- The amount remaining = Initial amount - (Rate × Time)
- Therefore: \(\mathrm{W = 40 - 4t}\)
3. SIMPLIFY by calculating values for each given time
- For \(\mathrm{t = 0}\) hours: \(\mathrm{W = 40 - 4(0)}\)
\(\mathrm{= 40 - 0}\)
\(\mathrm{= 40}\) gallons - For \(\mathrm{t = 1}\) hour: \(\mathrm{W = 40 - 4(1)}\)
\(\mathrm{= 40 - 4}\)
\(\mathrm{= 36}\) gallons - For \(\mathrm{t = 2}\) hours: \(\mathrm{W = 40 - 4(2)}\)
\(\mathrm{= 40 - 8}\)
\(\mathrm{= 32}\) gallons
4. APPLY CONSTRAINTS to select the correct table
- Look for the table showing: \(\mathrm{(0,40), (1,36), (2,32)}\)
- This matches Choice C exactly
Answer: C
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak TRANSLATE skill: Students misinterpret "drains at 4 gallons per hour" as meaning water increases by 4 gallons each hour, rather than decreases.
They might think: "4 gallons per hour means we add 4 each hour" and create the equation \(\mathrm{W = 40 + 4t}\) instead of \(\mathrm{W = 40 - 4t}\). This gives values of \(\mathrm{40, 44, 48}\) for \(\mathrm{t = 0, 1, 2}\).
This leads them to select Choice B (40, 44, 48).
Second Most Common Error:
Poor INFER reasoning: Students understand that water is draining but incorrectly think the tank starts empty and the "4 gallons per hour" represents some kind of loss that accumulates.
They might create \(\mathrm{W = -4t}\), giving values \(\mathrm{0, -4, -8}\) for \(\mathrm{t = 0, 1, 2}\), or they might think the problem is asking about total water drained rather than water remaining.
This may lead them to select Choice D (0, -4, -8) or Choice A (0, 4, 8).
The Bottom Line:
The key challenge is correctly interpreting "drains from" as subtraction from the initial amount, not addition to zero or some other starting point. Students must recognize that drainage represents a negative rate of change applied to the initial quantity.
| \(\mathrm{t}\) | \(\mathrm{W}\) |
|---|---|
| 0 | 0 |
| 1 | 4 |
| 2 | 8 |
| \(\mathrm{t}\) | \(\mathrm{W}\) |
|---|---|
| 0 | 40 |
| 1 | 44 |
| 2 | 48 |
| \(\mathrm{t}\) | \(\mathrm{W}\) |
|---|---|
| 0 | 40 |
| 1 | 36 |
| 2 | 32 |
| \(\mathrm{t}\) | \(\mathrm{W}\) |
|---|---|
| 0 | 0 |
| 1 | -4 |
| 2 | -8 |