A water tank is being drained at a constant rate. The relationship between the volume of water, V, in liters,...
GMAT Algebra : (Alg) Questions
A water tank is being drained at a constant rate. The relationship between the volume of water, \(\mathrm{V}\), in liters, in the tank and the time, \(\mathrm{t}\), in minutes, is linear. For every increase in \(\mathrm{t}\) by 1, the value of \(\mathrm{V}\) decreases by 15. When \(\mathrm{t = 3}\), the value of \(\mathrm{V}\) is 455. Which equation represents this relationship?
- \(\mathrm{V = -15t + 455}\)
- \(\mathrm{V = -15t + 500}\)
- \(\mathrm{V = -5t + 470}\)
- \(\mathrm{V = 15t + 410}\)
1. TRANSLATE the problem information
- Given information:
- Water tank draining at constant rate (linear relationship)
- For every 1-minute increase, volume decreases by 15 liters
- At \(\mathrm{t = 3}\) minutes, \(\mathrm{V = 455}\) liters
- Need equation in the form \(\mathrm{V = mt + b}\)
- What this tells us: We have a linear relationship with negative slope and one known point.
2. INFER the approach
- Since it's linear, we need slope (m) and y-intercept (b)
- The rate of change gives us the slope directly
- The given point will help us find the y-intercept
3. TRANSLATE the rate information to find slope
- "For every increase in t by 1, V decreases by 15"
- This means: \(\mathrm{slope = -15}\) (negative because decreasing)
- Our equation becomes: \(\mathrm{V = -15t + b}\)
4. INFER how to find the y-intercept
- Use the known point \(\mathrm{(3, 455)}\) in our equation
- Substitute \(\mathrm{t = 3}\) and \(\mathrm{V = 455}\) into \(\mathrm{V = -15t + b}\)
5. SIMPLIFY to solve for b
- \(\mathrm{455 = -15(3) + b}\)
- \(\mathrm{455 = -45 + b}\)
- \(\mathrm{455 + 45 = b}\)
- \(\mathrm{b = 500}\)
6. Write the final equation
- \(\mathrm{V = -15t + 500}\)
Answer: B
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak TRANSLATE skill: Misinterpreting "decreases by 15" as a positive slope instead of negative.
Students might think "by 15" means +15, leading them to write \(\mathrm{V = 15t + b}\). Using the point \(\mathrm{(3, 455)}\): \(\mathrm{455 = 15(3) + b}\) gives \(\mathrm{b = 410}\), producing \(\mathrm{V = 15t + 410}\).
This may lead them to select Choice D (\(\mathrm{V = 15t + 410}\)).
Second Most Common Error:
Poor SIMPLIFY execution: Making arithmetic errors when solving for the y-intercept.
Students correctly identify \(\mathrm{slope = -15}\) but make calculation mistakes: \(\mathrm{455 = -15(3) + b}\) becomes \(\mathrm{455 = -45 + b}\), but they might calculate \(\mathrm{455 - 45 = 410}\) instead of \(\mathrm{455 + 45 = 500}\). This gives \(\mathrm{V = -15t + 410}\), but this option doesn't exist, leading to confusion and potentially selecting the similar-looking Choice A (\(\mathrm{V = -15t + 455}\)).
The Bottom Line:
This problem tests whether students can accurately translate rate language into mathematical slope and then execute the algebra correctly to find the complete linear equation.