A wire with a length of 106 inches is cut into two parts. One part has a length of x...
GMAT Algebra : (Alg) Questions
A wire with a length of \(\mathrm{106}\) inches is cut into two parts. One part has a length of \(\mathrm{x}\) inches, and the other part has a length of \(\mathrm{y}\) inches. The value of \(\mathrm{x}\) is \(\mathrm{6}\) more than \(\mathrm{4}\) times the value of \(\mathrm{y}\). What is the value of \(\mathrm{x}\)?
\(\mathrm{25}\)
\(\mathrm{28}\)
\(\mathrm{56}\)
\(\mathrm{86}\)
1. TRANSLATE the problem information
- Given information:
- Total wire length: 106 inches
- Wire cut into two parts: \(\mathrm{x}\) inches and \(\mathrm{y}\) inches
- "x is 6 more than 4 times y"
- This gives us two equations:
- \(\mathrm{x + y = 106}\) (the parts add up to the whole)
- \(\mathrm{x = 4y + 6}\) (the relationship between x and y)
2. INFER the solution approach
- We have a system of two equations with two unknowns
- Since the second equation already expresses x in terms of y, substitution is the most efficient method
- We'll substitute the expression for x into the first equation
3. SIMPLIFY by substitution
- Substitute \(\mathrm{x = 4y + 6}\) into \(\mathrm{x + y = 106}\):
\(\mathrm{(4y + 6) + y = 106}\)
\(\mathrm{5y + 6 = 106}\)
\(\mathrm{5y = 100}\)
\(\mathrm{y = 20}\)
4. SIMPLIFY to find x
- Use \(\mathrm{y = 20}\) in the equation \(\mathrm{x = 4y + 6}\):
\(\mathrm{x = 4(20) + 6 = 80 + 6 = 86}\)
Answer: D. 86
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak TRANSLATE skill: Misinterpreting "x is 6 more than 4 times y" as "x is 6 more than y"
Students often rush through reading and miss the "4 times" part, setting up the incorrect equation \(\mathrm{x = y + 6}\) instead of \(\mathrm{x = 4y + 6}\). With \(\mathrm{x + y = 106}\) and \(\mathrm{x = y + 6}\), they solve to get \(\mathrm{y = 50}\) and \(\mathrm{x = 56}\).
This may lead them to select Choice C (56)
Second Most Common Error:
Poor SIMPLIFY execution: Arithmetic mistakes during algebraic manipulation
Students correctly set up the equations but make calculation errors, such as:
- \(\mathrm{5y + 6 = 106}\) → \(\mathrm{5y = 99}\) (forgetting to subtract 6 properly)
- Dividing incorrectly when solving for y
- Making errors when calculating \(\mathrm{x = 4(20) + 6}\)
This leads to confusion and various wrong values, potentially causing them to guess among the remaining choices.
The Bottom Line:
This problem tests both careful reading comprehension and systematic equation-solving. Students who rush through the translation phase or aren't methodical with their algebra often select incorrect answers that seem reasonable but don't satisfy both original conditions.
\(\mathrm{25}\)
\(\mathrm{28}\)
\(\mathrm{56}\)
\(\mathrm{86}\)