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A wire with a length of 106 inches is cut into two parts. One part has a length of x...

GMAT Algebra : (Alg) Questions

Source: Practice Test
Algebra
Systems of 2 linear equations in 2 variables
MEDIUM
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Notes
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A wire with a length of \(\mathrm{106}\) inches is cut into two parts. One part has a length of \(\mathrm{x}\) inches, and the other part has a length of \(\mathrm{y}\) inches. The value of \(\mathrm{x}\) is \(\mathrm{6}\) more than \(\mathrm{4}\) times the value of \(\mathrm{y}\). What is the value of \(\mathrm{x}\)?

A

\(\mathrm{25}\)

B

\(\mathrm{28}\)

C

\(\mathrm{56}\)

D

\(\mathrm{86}\)

Solution

1. TRANSLATE the problem information

  • Given information:
    • Total wire length: 106 inches
    • Wire cut into two parts: \(\mathrm{x}\) inches and \(\mathrm{y}\) inches
    • "x is 6 more than 4 times y"
  • This gives us two equations:
    • \(\mathrm{x + y = 106}\) (the parts add up to the whole)
    • \(\mathrm{x = 4y + 6}\) (the relationship between x and y)

2. INFER the solution approach

  • We have a system of two equations with two unknowns
  • Since the second equation already expresses x in terms of y, substitution is the most efficient method
  • We'll substitute the expression for x into the first equation

3. SIMPLIFY by substitution

  • Substitute \(\mathrm{x = 4y + 6}\) into \(\mathrm{x + y = 106}\):

\(\mathrm{(4y + 6) + y = 106}\)
\(\mathrm{5y + 6 = 106}\)
\(\mathrm{5y = 100}\)
\(\mathrm{y = 20}\)

4. SIMPLIFY to find x

  • Use \(\mathrm{y = 20}\) in the equation \(\mathrm{x = 4y + 6}\):

\(\mathrm{x = 4(20) + 6 = 80 + 6 = 86}\)

Answer: D. 86




Why Students Usually Falter on This Problem

Most Common Error Path:

Weak TRANSLATE skill: Misinterpreting "x is 6 more than 4 times y" as "x is 6 more than y"

Students often rush through reading and miss the "4 times" part, setting up the incorrect equation \(\mathrm{x = y + 6}\) instead of \(\mathrm{x = 4y + 6}\). With \(\mathrm{x + y = 106}\) and \(\mathrm{x = y + 6}\), they solve to get \(\mathrm{y = 50}\) and \(\mathrm{x = 56}\).

This may lead them to select Choice C (56)

Second Most Common Error:

Poor SIMPLIFY execution: Arithmetic mistakes during algebraic manipulation

Students correctly set up the equations but make calculation errors, such as:

  • \(\mathrm{5y + 6 = 106}\)\(\mathrm{5y = 99}\) (forgetting to subtract 6 properly)
  • Dividing incorrectly when solving for y
  • Making errors when calculating \(\mathrm{x = 4(20) + 6}\)

This leads to confusion and various wrong values, potentially causing them to guess among the remaining choices.

The Bottom Line:

This problem tests both careful reading comprehension and systematic equation-solving. Students who rush through the translation phase or aren't methodical with their algebra often select incorrect answers that seem reasonable but don't satisfy both original conditions.

Answer Choices Explained
A

\(\mathrm{25}\)

B

\(\mathrm{28}\)

C

\(\mathrm{56}\)

D

\(\mathrm{86}\)

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