Question:x = 10\(\mathrm{x = -2(y - 4)^2 + 8}\)If the given equations are graphed in the xy-plane, at how many...
GMAT Advanced Math : (Adv_Math) Questions
\(\mathrm{x = 10}\)
\(\mathrm{x = -2(y - 4)^2 + 8}\)
If the given equations are graphed in the xy-plane, at how many points do the graphs of the equations intersect?
Exactly one
Exactly two
Infinitely many
Zero
1. TRANSLATE the problem information
- Given equations:
- \(\mathrm{x = 10}\) (vertical line)
- \(\mathrm{x = -2(y - 4)^2 + 8}\) (parabola)
- Need to find: Number of intersection points
2. INFER the solution approach
- Since we want intersections, we need points that satisfy both equations simultaneously
- Both expressions equal x, so we can set them equal to each other: \(\mathrm{10 = -2(y - 4)^2 + 8}\)
3. SIMPLIFY the equation
- Start with: \(\mathrm{10 = -2(y - 4)^2 + 8}\)
- Subtract 8 from both sides: \(\mathrm{2 = -2(y - 4)^2}\)
- Divide both sides by -2: \(\mathrm{-1 = (y - 4)^2}\)
4. INFER the final conclusion
- We need \(\mathrm{(y - 4)^2 = -1}\)
- But squares of real numbers are always non-negative: \(\mathrm{(y - 4)^2 \geq 0}\)
- Since \(\mathrm{-1 \lt 0}\), this equation has no real solutions
- No solutions means no intersection points
Answer: D (Zero)
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak INFER skill: Not recognizing that squares of real numbers cannot be negative
Students correctly arrive at \(\mathrm{(y - 4)^2 = -1}\) but then attempt to solve it by taking the square root of both sides, writing \(\mathrm{y - 4 = \pm\sqrt{-1}}\). They might either get confused by the imaginary numbers or incorrectly think this gives real solutions. This leads to confusion and guessing among the answer choices.
Second Most Common Error:
Poor TRANSLATE reasoning: Setting up the system incorrectly
Some students might try to solve this by substituting the first equation into the second equation incorrectly, such as writing \(\mathrm{10 = -2(10 - 4)^2 + 8}\), thinking they should substitute \(\mathrm{x = 10}\) into the y-variable position. This algebraic error leads them away from the systematic approach and typically results in guessing.
The Bottom Line:
This problem tests whether students understand both the systematic approach to finding intersections (setting equal expressions equal) and the fundamental property that squares of real numbers are non-negative. The key insight is recognizing when an equation has no real solutions.
Exactly one
Exactly two
Infinitely many
Zero