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Question:x = 10\(\mathrm{x = -2(y - 4)^2 + 8}\)If the given equations are graphed in the xy-plane, at how many...

GMAT Advanced Math : (Adv_Math) Questions

Source: Prism
Advanced Math
Nonlinear equations in 1 variable
HARD
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Notes
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Question:

\(\mathrm{x = 10}\)
\(\mathrm{x = -2(y - 4)^2 + 8}\)

If the given equations are graphed in the xy-plane, at how many points do the graphs of the equations intersect?

A

Exactly one

B

Exactly two

C

Infinitely many

D

Zero

Solution

1. TRANSLATE the problem information

  • Given equations:
    • \(\mathrm{x = 10}\) (vertical line)
    • \(\mathrm{x = -2(y - 4)^2 + 8}\) (parabola)
  • Need to find: Number of intersection points

2. INFER the solution approach

  • Since we want intersections, we need points that satisfy both equations simultaneously
  • Both expressions equal x, so we can set them equal to each other: \(\mathrm{10 = -2(y - 4)^2 + 8}\)

3. SIMPLIFY the equation

  • Start with: \(\mathrm{10 = -2(y - 4)^2 + 8}\)
  • Subtract 8 from both sides: \(\mathrm{2 = -2(y - 4)^2}\)
  • Divide both sides by -2: \(\mathrm{-1 = (y - 4)^2}\)

4. INFER the final conclusion

  • We need \(\mathrm{(y - 4)^2 = -1}\)
  • But squares of real numbers are always non-negative: \(\mathrm{(y - 4)^2 \geq 0}\)
  • Since \(\mathrm{-1 \lt 0}\), this equation has no real solutions
  • No solutions means no intersection points

Answer: D (Zero)




Why Students Usually Falter on This Problem

Most Common Error Path:

Weak INFER skill: Not recognizing that squares of real numbers cannot be negative

Students correctly arrive at \(\mathrm{(y - 4)^2 = -1}\) but then attempt to solve it by taking the square root of both sides, writing \(\mathrm{y - 4 = \pm\sqrt{-1}}\). They might either get confused by the imaginary numbers or incorrectly think this gives real solutions. This leads to confusion and guessing among the answer choices.

Second Most Common Error:

Poor TRANSLATE reasoning: Setting up the system incorrectly

Some students might try to solve this by substituting the first equation into the second equation incorrectly, such as writing \(\mathrm{10 = -2(10 - 4)^2 + 8}\), thinking they should substitute \(\mathrm{x = 10}\) into the y-variable position. This algebraic error leads them away from the systematic approach and typically results in guessing.

The Bottom Line:

This problem tests whether students understand both the systematic approach to finding intersections (setting equal expressions equal) and the fundamental property that squares of real numbers are non-negative. The key insight is recognizing when an equation has no real solutions.

Answer Choices Explained
A

Exactly one

B

Exactly two

C

Infinitely many

D

Zero

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