If \((\mathrm{x} + 5)^2 = 4\), which of the following is a possible value of x?
GMAT Advanced Math : (Adv_Math) Questions
If \((\mathrm{x} + 5)^2 = 4\), which of the following is a possible value of \(\mathrm{x}\)?
\(1\)
\(-1\)
\(-2\)
\(-3\)
1. TRANSLATE the problem information
- Given: \((\mathrm{x} + 5)^2 = 4\)
- Find: Possible values of x from the given choices
2. CONSIDER ALL CASES when taking square roots
- When we have \((\mathrm{x} + 5)^2 = 4\), taking the square root of both sides gives us:
\(\mathrm{x} + 5 = ±2\) - This means we have TWO equations to solve:
- \(\mathrm{x} + 5 = 2\) (positive case)
- \(\mathrm{x} + 5 = -2\) (negative case)
3. SIMPLIFY each linear equation
- From \(\mathrm{x} + 5 = 2\):
\(\mathrm{x} = 2 - 5\)
\(\mathrm{x} = -3\)
- From \(\mathrm{x} + 5 = -2\):
\(\mathrm{x} = -2 - 5\)
\(\mathrm{x} = -7\)
4. Check which solutions appear in answer choices
- Our solutions are \(\mathrm{x} = -3\) and \(\mathrm{x} = -7\)
- Looking at choices: A. 1, B. -1, C. -2, D. -3
- Only \(\mathrm{x} = -3\) appears as choice D
Answer: D
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak CONSIDER ALL CASES skill: Students forget that taking the square root gives both positive and negative solutions. They might only solve \(\mathrm{x} + 5 = 2\), finding \(\mathrm{x} = -3\), but miss the \(\mathrm{x} + 5 = -2\) case entirely. While this still leads to the correct answer in this particular problem, it shows incomplete understanding that could cause errors in future problems.
Second Most Common Error:
Poor TRANSLATE reasoning: Students misread \((\mathrm{x} + 5)^2 = 4\) as \(\mathrm{x} + 5 = 4\), then solve to get \(\mathrm{x} = -1\). This leads them to select Choice B (-1).
Third Most Common Error:
TRANSLATE confusion about what to find: Students correctly find that \(\mathrm{x} + 5 = ±2\), but then give -2 as their final answer (confusing the value of \(\mathrm{x} + 5\) with the value of \(\mathrm{x}\)). This may lead them to select Choice C (-2).
The Bottom Line:
This problem tests whether students understand that square root operations produce two solutions and can distinguish between solving for an expression versus solving for the variable itself.
\(1\)
\(-1\)
\(-2\)
\(-3\)