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x^2 - bx + 15 = 0 In the equation above, b is a positive constant. If the equation has...

GMAT Advanced Math : (Adv_Math) Questions

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Advanced Math
Nonlinear equations in 1 variable
MEDIUM
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Notes
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\(\mathrm{x^2 - bx + 15 = 0}\)

In the equation above, \(\mathrm{b}\) is a positive constant. If the equation has two positive integer solutions and the difference between the larger solution and the smaller solution is \(\mathrm{2}\), what is the value of \(\mathrm{b}\)?

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Solution

1. TRANSLATE the problem information

  • Given information:
    • Quadratic equation: \(\mathrm{x^2 - bx + 15 = 0}\)
    • b is positive
    • Two positive integer solutions
    • Difference between larger and smaller solution is 2
    • Find the value of b

2. INFER the strategic approach

  • Since we need relationships between the roots and coefficient b, Vieta's formulas are perfect here
  • Let the two solutions be r and s where \(\mathrm{r \gt s}\)
  • We can use both the sum and product relationships

3. Apply Vieta's formulas

For \(\mathrm{x^2 - bx + 15 = 0}\):

  • Sum of roots: \(\mathrm{r + s = b}\)
  • Product of roots: \(\mathrm{rs = 15}\)

4. CONSIDER ALL CASES for factor pairs

Since both roots are positive integers with product 15, find all factor pairs:

  • \(\mathrm{1 × 15 = 15}\)
  • \(\mathrm{3 × 5 = 15}\)

5. APPLY CONSTRAINTS using the difference condition

Check which pair has difference 2:

  • \(\mathrm{15 - 1 = 14 ≠ 2}\)
  • \(\mathrm{5 - 3 = 2}\)

Therefore: \(\mathrm{r = 5, s = 3}\)

6. Calculate b

\(\mathrm{b = r + s = 5 + 3 = 8}\)

Answer: 8


Why Students Usually Falter on This Problem

Most Common Error Path:

Weak INFER skill: Students don't recognize that Vieta's formulas provide the direct connection between roots and coefficients. Instead, they might try to guess and check values of b or attempt to factor without a systematic approach.

This leads to confusion and abandoning systematic solution, resulting in guessing.

Second Most Common Error:

Poor APPLY CONSTRAINTS execution: Students find the factor pairs of 15 but forget to check the difference condition. They might immediately conclude that \(\mathrm{b = 1 + 15 = 16}\) using the first factor pair they find.

This may lead them to select an incorrect answer if 16 were among the choices.

The Bottom Line:

This problem requires connecting abstract algebraic relationships (Vieta's formulas) with concrete number properties (factor pairs and differences). Students who miss the Vieta's formulas connection often get lost trying random approaches.

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