What is an x-coordinate of an x-intercept of the graph of \(\mathrm{y = 3(x - 14)(x + 5)(x + 4)}\)...
GMAT Advanced Math : (Adv_Math) Questions
What is an x-coordinate of an x-intercept of the graph of \(\mathrm{y = 3(x - 14)(x + 5)(x + 4)}\) in the xy-plane?
1. TRANSLATE the problem information
- Given: \(\mathrm{y = 3(x - 14)(x + 5)(x + 4)}\)
- Need: x-coordinate of an x-intercept
- What this tells us: X-intercepts occur where the graph crosses the x-axis, so \(\mathrm{y = 0}\)
2. INFER the solving approach
- Since the polynomial is already in factored form, we can use the zero product property
- Set the equation equal to zero: \(\mathrm{0 = 3(x - 14)(x + 5)(x + 4)}\)
- The factor of 3 doesn't affect where \(\mathrm{y = 0}\), so we can focus on: \(\mathrm{0 = (x - 14)(x + 5)(x + 4)}\)
3. APPLY the zero product property
- If a product equals zero, at least one factor must equal zero
- This gives us three equations to solve:
- \(\mathrm{x - 14 = 0}\)
- \(\mathrm{x + 5 = 0}\)
- \(\mathrm{x + 4 = 0}\)
4. SIMPLIFY each linear equation
- From \(\mathrm{x - 14 = 0}\): \(\mathrm{x = 14}\)
- From \(\mathrm{x + 5 = 0}\): \(\mathrm{x = -5}\)
- From \(\mathrm{x + 4 = 0}\): \(\mathrm{x = -4}\)
Answer: 14, -5, or -4 (any one of these is correct)
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak TRANSLATE skill: Students may not connect "x-intercept" with the condition \(\mathrm{y = 0}\), instead trying to solve for when \(\mathrm{x = 0}\) or attempting to find the vertex. This fundamental misunderstanding leads to confusion and abandoning systematic solution.
Second Most Common Error:
Poor SIMPLIFY execution: Students correctly set up the zero product property but make sign errors when solving the linear equations, particularly confusing \(\mathrm{x + 5 = 0 \rightarrow x = 5}\) instead of \(\mathrm{x = -5}\). This leads them to provide incorrect x-coordinates like 5 or 4 instead of the correct values.
The Bottom Line:
This problem tests whether students understand what x-intercepts represent and can execute the zero product property correctly. The factored form makes it straightforward once students recognize the connection between intercepts and \(\mathrm{y = 0}\).