The expression \((\mathrm{x} + 2)(3\mathrm{x} - 1) + 7\mathrm{x} + 15\) can be written in the form ax^2 + bx...
GMAT Advanced Math : (Adv_Math) Questions
The expression \((\mathrm{x} + 2)(3\mathrm{x} - 1) + 7\mathrm{x} + 15\) can be written in the form \(\mathrm{ax}^2 + \mathrm{bx} + \mathrm{c}\), where \(\mathrm{a}\), \(\mathrm{b}\), and \(\mathrm{c}\) are constants. What is the value of \(\mathrm{a} + \mathrm{b} + \mathrm{c}\)?
15
27
28
32
1. TRANSLATE the problem information
- Given: Expression \((x + 2)(3x - 1) + 7x + 15\) needs to be written as \(ax² + bx + c\)
- Find: The value of \(a + b + c\)
2. SIMPLIFY by expanding the binomial product first
- Use the distributive property on \((x + 2)(3x - 1)\):
- \(x(3x - 1) = 3x² - x\)
- \(2(3x - 1) = 6x - 2\)
- Combined: \((x + 2)(3x - 1) = 3x² - x + 6x - 2 = 3x² + 5x - 2\)
3. SIMPLIFY by adding the remaining terms
- Now we have: \(3x² + 5x - 2 + 7x + 15\)
- Combine like terms:
- \(x²\) terms: \(3x²\) (only one)
- \(x\) terms: \(5x + 7x = 12x\)
- Constant terms: \(-2 + 15 = 13\)
- Final form: \(3x² + 12x + 13\)
4. TRANSLATE to identify coefficients
- In the form \(ax² + bx + c\): \(a = 3, b = 12, c = 13\)
- Therefore: \(a + b + c = 3 + 12 + 13 = 28\)
Answer: C) 28
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak SIMPLIFY execution: Students make errors when expanding \((x + 2)(3x - 1)\), particularly with the middle terms or signs.
For example, they might get \(3x² - x + 6x - 2 = 3x² + 5x - 2\) wrong by calculating the middle terms incorrectly as \(3x² + 7x - 2\) or \(3x² + 4x - 2\). This leads to different values for the x-coefficient, resulting in a wrong final sum. They might select Choice B (27) or Choice A (15) depending on their specific error.
Second Most Common Error:
Arithmetic mistakes in SIMPLIFY: Students correctly expand the binomial but make errors when combining the x-terms \((5x + 7x)\) or constant terms \((-2 + 15)\).
Getting \(5x + 7x = 11x\) instead of \(12x\) would give them \(a = 3, b = 11, c = 13\), leading to \(a + b + c = 27\). This may lead them to select Choice B (27).
The Bottom Line:
This problem requires careful step-by-step algebraic manipulation. Success depends on systematic expansion of the binomial product and methodical combining of like terms—both areas where small errors compound into wrong final answers.
15
27
28
32