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Question:Let p be a positive constant, and suppose |x| gt p. The value of x satisfies \((\mathrm{x}^2 - \mathrm{p}^2)^2 =...

GMAT Advanced Math : (Adv_Math) Questions

Source: Prism
Advanced Math
Nonlinear equations in 1 variable
HARD
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Question:

Let p be a positive constant, and suppose \(|\mathrm{x}| \gt \mathrm{p}\). The value of x satisfies \((\mathrm{x}^2 - \mathrm{p}^2)^2 = 1600(\mathrm{x}^2 - \mathrm{p}^2)\). Which of the following is one solution for x?

A

\(-\mathrm{p}\)

B

\(-\mathrm{p}^2 - 40^2\)

C

\(-\sqrt{40^2 - \mathrm{p}^2}\)

D

\(-\sqrt{\mathrm{p}^2 + 40^2}\)

Solution

1. TRANSLATE the problem information

  • Given information:
    • p is a positive constant
    • \(|\mathrm{x}| \gt \mathrm{p}\) (x is farther from zero than p)
    • \((\mathrm{x}^2 - \mathrm{p}^2)^2 = 1600(\mathrm{x}^2 - \mathrm{p}^2)\)
    • Need to find which answer choice is a solution

2. INFER a strategic substitution

  • The expression \((\mathrm{x}^2 - \mathrm{p}^2)\) appears twice in our equation
  • Let \(\mathrm{y} = \mathrm{x}^2 - \mathrm{p}^2\) to simplify the equation
  • This transforms our equation to: \(\mathrm{y}^2 = 1600\mathrm{y}\)

3. APPLY CONSTRAINTS to determine the sign of y

  • Since \(|\mathrm{x}| \gt \mathrm{p}\), we know \(\mathrm{x}^2 \gt \mathrm{p}^2\)
  • Therefore \(\mathrm{y} = \mathrm{x}^2 - \mathrm{p}^2 \gt 0\)
  • This constraint will be crucial for selecting the correct solution

4. SIMPLIFY the quadratic equation

  • Starting with \(\mathrm{y}^2 = 1600\mathrm{y}\)
  • Rearrange: \(\mathrm{y}^2 - 1600\mathrm{y} = 0\)
  • Factor: \(\mathrm{y}(\mathrm{y} - 1600) = 0\)
  • Solutions: \(\mathrm{y} = 0\) or \(\mathrm{y} = 1600\)

5. APPLY CONSTRAINTS to select valid solution

  • Since \(\mathrm{y} \gt 0\) (from step 3), we reject \(\mathrm{y} = 0\)
  • Therefore \(\mathrm{y} = 1600\)

6. INFER the final step and SIMPLIFY

  • Substitute back: \(\mathrm{x}^2 - \mathrm{p}^2 = 1600\)
  • Solve for \(\mathrm{x}^2\): \(\mathrm{x}^2 = \mathrm{p}^2 + 1600\)
  • Recognize that \(1600 = 40^2\): \(\mathrm{x}^2 = \mathrm{p}^2 + 40^2\)
  • Take square root: \(\mathrm{x} = ±\sqrt{\mathrm{p}^2 + 40^2}\)

7. APPLY CONSTRAINTS to match answer choices

  • Both \(\mathrm{x} = \sqrt{\mathrm{p}^2 + 40^2}\) and \(\mathrm{x} = -\sqrt{\mathrm{p}^2 + 40^2}\) are valid mathematically
  • Looking at the choices, only \(-\sqrt{\mathrm{p}^2 + 40^2}\) appears

Answer: D




Why Students Usually Falter on This Problem


Most Common Error Path:

Weak INFER skill: Students often get overwhelmed by the complex appearance of \((\mathrm{x}^2 - \mathrm{p}^2)^2 = 1600(\mathrm{x}^2 - \mathrm{p}^2)\) and try to expand everything instead of recognizing the substitution opportunity.

Without the substitution \(\mathrm{y} = \mathrm{x}^2 - \mathrm{p}^2\), they attempt to expand \((\mathrm{x}^2 - \mathrm{p}^2)^2\) and work with a quartic equation, leading to complicated algebra that's prone to errors. This often causes them to abandon systematic solution and guess.


Second Most Common Error:

Poor APPLY CONSTRAINTS reasoning: Students correctly find \(\mathrm{y} = 0\) or \(\mathrm{y} = 1600\) but forget to use the constraint \(|\mathrm{x}| \gt \mathrm{p}\), which means \(\mathrm{y} \gt 0\).

They accept \(\mathrm{y} = 0\), leading to \(\mathrm{x}^2 = \mathrm{p}^2\), so \(\mathrm{x} = ±\mathrm{p}\). Seeing \(-\mathrm{p}\) among the choices, they select Choice A (\(-\mathrm{p}\)) without recognizing this violates the original constraint \(|\mathrm{x}| \gt \mathrm{p}\).


The Bottom Line:

This problem tests whether students can recognize when substitution simplifies complex expressions and whether they remember to apply all given constraints throughout their solution.

Answer Choices Explained
A

\(-\mathrm{p}\)

B

\(-\mathrm{p}^2 - 40^2\)

C

\(-\sqrt{40^2 - \mathrm{p}^2}\)

D

\(-\sqrt{\mathrm{p}^2 + 40^2}\)

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