Question:Let p be a positive constant, and suppose |x| gt p. The value of x satisfies \((\mathrm{x}^2 - \mathrm{p}^2)^2 =...
GMAT Advanced Math : (Adv_Math) Questions
Let p be a positive constant, and suppose \(|\mathrm{x}| \gt \mathrm{p}\). The value of x satisfies \((\mathrm{x}^2 - \mathrm{p}^2)^2 = 1600(\mathrm{x}^2 - \mathrm{p}^2)\). Which of the following is one solution for x?
\(-\mathrm{p}\)
\(-\mathrm{p}^2 - 40^2\)
\(-\sqrt{40^2 - \mathrm{p}^2}\)
\(-\sqrt{\mathrm{p}^2 + 40^2}\)
1. TRANSLATE the problem information
- Given information:
- p is a positive constant
- \(|\mathrm{x}| \gt \mathrm{p}\) (x is farther from zero than p)
- \((\mathrm{x}^2 - \mathrm{p}^2)^2 = 1600(\mathrm{x}^2 - \mathrm{p}^2)\)
- Need to find which answer choice is a solution
2. INFER a strategic substitution
- The expression \((\mathrm{x}^2 - \mathrm{p}^2)\) appears twice in our equation
- Let \(\mathrm{y} = \mathrm{x}^2 - \mathrm{p}^2\) to simplify the equation
- This transforms our equation to: \(\mathrm{y}^2 = 1600\mathrm{y}\)
3. APPLY CONSTRAINTS to determine the sign of y
- Since \(|\mathrm{x}| \gt \mathrm{p}\), we know \(\mathrm{x}^2 \gt \mathrm{p}^2\)
- Therefore \(\mathrm{y} = \mathrm{x}^2 - \mathrm{p}^2 \gt 0\)
- This constraint will be crucial for selecting the correct solution
4. SIMPLIFY the quadratic equation
- Starting with \(\mathrm{y}^2 = 1600\mathrm{y}\)
- Rearrange: \(\mathrm{y}^2 - 1600\mathrm{y} = 0\)
- Factor: \(\mathrm{y}(\mathrm{y} - 1600) = 0\)
- Solutions: \(\mathrm{y} = 0\) or \(\mathrm{y} = 1600\)
5. APPLY CONSTRAINTS to select valid solution
- Since \(\mathrm{y} \gt 0\) (from step 3), we reject \(\mathrm{y} = 0\)
- Therefore \(\mathrm{y} = 1600\)
6. INFER the final step and SIMPLIFY
- Substitute back: \(\mathrm{x}^2 - \mathrm{p}^2 = 1600\)
- Solve for \(\mathrm{x}^2\): \(\mathrm{x}^2 = \mathrm{p}^2 + 1600\)
- Recognize that \(1600 = 40^2\): \(\mathrm{x}^2 = \mathrm{p}^2 + 40^2\)
- Take square root: \(\mathrm{x} = ±\sqrt{\mathrm{p}^2 + 40^2}\)
7. APPLY CONSTRAINTS to match answer choices
- Both \(\mathrm{x} = \sqrt{\mathrm{p}^2 + 40^2}\) and \(\mathrm{x} = -\sqrt{\mathrm{p}^2 + 40^2}\) are valid mathematically
- Looking at the choices, only \(-\sqrt{\mathrm{p}^2 + 40^2}\) appears
Answer: D
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak INFER skill: Students often get overwhelmed by the complex appearance of \((\mathrm{x}^2 - \mathrm{p}^2)^2 = 1600(\mathrm{x}^2 - \mathrm{p}^2)\) and try to expand everything instead of recognizing the substitution opportunity.
Without the substitution \(\mathrm{y} = \mathrm{x}^2 - \mathrm{p}^2\), they attempt to expand \((\mathrm{x}^2 - \mathrm{p}^2)^2\) and work with a quartic equation, leading to complicated algebra that's prone to errors. This often causes them to abandon systematic solution and guess.
Second Most Common Error:
Poor APPLY CONSTRAINTS reasoning: Students correctly find \(\mathrm{y} = 0\) or \(\mathrm{y} = 1600\) but forget to use the constraint \(|\mathrm{x}| \gt \mathrm{p}\), which means \(\mathrm{y} \gt 0\).
They accept \(\mathrm{y} = 0\), leading to \(\mathrm{x}^2 = \mathrm{p}^2\), so \(\mathrm{x} = ±\mathrm{p}\). Seeing \(-\mathrm{p}\) among the choices, they select Choice A (\(-\mathrm{p}\)) without recognizing this violates the original constraint \(|\mathrm{x}| \gt \mathrm{p}\).
The Bottom Line:
This problem tests whether students can recognize when substitution simplifies complex expressions and whether they remember to apply all given constraints throughout their solution.
\(-\mathrm{p}\)
\(-\mathrm{p}^2 - 40^2\)
\(-\sqrt{40^2 - \mathrm{p}^2}\)
\(-\sqrt{\mathrm{p}^2 + 40^2}\)