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Circle A has equation \(\mathrm{x^2 + (y - 3)^2 = 16}\). Circle B is obtained by reflecting circle A across...

GMAT Geometry & Trigonometry : (Geo_Trig) Questions

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Geometry & Trigonometry
Circles
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Circle A has equation \(\mathrm{x^2 + (y - 3)^2 = 16}\). Circle B is obtained by reflecting circle A across the x-axis. Which of the following equations represents circle B?

A

\(\mathrm{x^2 + (y - 3)^2 = 16}\)

B

\(\mathrm{x^2 + (y + 3)^2 = 16}\)

C

\(\mathrm{(x - 3)^2 + y^2 = 16}\)

D

\(\mathrm{x^2 + (-y + 3)^2 = 16}\)

Solution

1. TRANSLATE the given information

  • Given: Circle A has equation \(\mathrm{x^2 + (y - 3)^2 = 16}\)
  • Need: Equation of Circle B after reflecting Circle A across the x-axis

2. INFER the center and radius of Circle A

  • From standard form \(\mathrm{(x - h)^2 + (y - k)^2 = r^2}\):
    • Center: \(\mathrm{(0, 3)}\)
    • Radius: \(\mathrm{\sqrt{16} = 4}\)

3. TRANSLATE the reflection rule

  • Reflecting across the x-axis means:
    • x-coordinate stays the same
    • y-coordinate changes sign
  • So point \(\mathrm{(0, 3)}\) becomes \(\mathrm{(0, -3)}\)

4. INFER what changes and what stays the same

  • Circle B will have:
    • Same x-coordinate: 0
    • New y-coordinate: -3
    • Same radius: 4

5. SIMPLIFY to write Circle B's equation

  • Center \(\mathrm{(0, -3)}\) and radius 4 gives us:
  • \(\mathrm{x^2 + (y - (-3))^2 = 16}\)
  • \(\mathrm{x^2 + (y + 3)^2 = 16}\)

Answer: B




Why Students Usually Falter on This Problem

Most Common Error Path:

Weak TRANSLATE skill: Students incorrectly interpret "reflecting across the x-axis" and think both coordinates change, or they get confused about which coordinate changes sign.

They might think the x-coordinate changes instead, leading them to move the center from \(\mathrm{(0, 3)}\) to \(\mathrm{(-3, 0)}\), which would give equation \(\mathrm{(x + 3)^2 + (y - 3)^2 = 16}\). Since this isn't an option, they get confused and may select Choice C (\(\mathrm{(x - 3)^2 + y^2 = 16}\)) thinking it's somehow related to moving coordinates around.

Second Most Common Error:

Poor SIMPLIFY execution: Students correctly identify that the center becomes \(\mathrm{(0, -3)}\) but make an algebra error when writing the equation.

They might write \(\mathrm{x^2 + (y - (-3))^2 = 16}\) but then incorrectly simplify this as \(\mathrm{x^2 + (-y + 3)^2 = 16}\), leading them to select Choice D.

The Bottom Line:

This problem tests whether students truly understand coordinate transformations and can systematically apply the reflection rule while maintaining careful algebra throughout.

Answer Choices Explained
A

\(\mathrm{x^2 + (y - 3)^2 = 16}\)

B

\(\mathrm{x^2 + (y + 3)^2 = 16}\)

C

\(\mathrm{(x - 3)^2 + y^2 = 16}\)

D

\(\mathrm{x^2 + (-y + 3)^2 = 16}\)

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