y = -4x + 40 Which table gives three values of x and their corresponding values of y for the...
GMAT Algebra : (Alg) Questions
\(\mathrm{y = -4x + 40}\)
Which table gives three values of x and their corresponding values of y for the given equation?
| x | y |
|---|---|
| 0 | 0 |
| 1 | -4 |
| 2 | -8 |
| x | y |
|---|---|
| 0 | 40 |
| 1 | 44 |
| 2 | 48 |
| x | y |
|---|---|
| 0 | 40 |
| 1 | 36 |
| 2 | 32 |
| x | y |
|---|---|
| 0 | 0 |
| 1 | 4 |
| 2 | 8 |
1. TRANSLATE the problem requirements
- Given information:
- Linear equation: \(\mathrm{y = -4x + 40}\)
- Need to find y values when \(\mathrm{x = 0}\), \(\mathrm{1}\), and \(\mathrm{2}\)
- What this means: I need to substitute each x value into the equation and calculate the corresponding y value
2. SIMPLIFY by substituting each x value systematically
For x = 0:
- \(\mathrm{y = -4(0) + 40}\)
- \(\mathrm{y = 0 + 40 = 40}\)
For x = 1:
- \(\mathrm{y = -4(1) + 40}\)
- \(\mathrm{y = -4 + 40 = 36}\)
For x = 2:
- \(\mathrm{y = -4(2) + 40}\)
- \(\mathrm{y = -8 + 40 = 32}\)
3. TRANSLATE results to identify the correct table
- The correct table should show: \(\mathrm{(0,40), (1,36), (2,32)}\)
- Checking each choice, only Choice C matches these values exactly
Answer: C
Why Students Usually Falter on This Problem
Most Common Error Path:
Weak SIMPLIFY skill: Students make sign errors with the negative coefficient, calculating \(\mathrm{y = 4x + 40}\) instead of \(\mathrm{y = -4x + 40}\)
When \(\mathrm{x = 1}\): \(\mathrm{y = 4(1) + 40 = 44}\) (instead of 36)
When \(\mathrm{x = 2}\): \(\mathrm{y = 4(2) + 40 = 48}\) (instead of 32)
This leads them to select Choice B (showing values 44 and 48)
Second Most Common Error:
Poor TRANSLATE reasoning: Students misunderstand the equation structure and ignore the constant term, calculating only \(\mathrm{y = -4x}\)
When \(\mathrm{x = 0}\): \(\mathrm{y = -4(0) = 0}\) (instead of 40)
When \(\mathrm{x = 1}\): \(\mathrm{y = -4(1) = -4}\) (instead of 36)
When \(\mathrm{x = 2}\): \(\mathrm{y = -4(2) = -8}\) (instead of 32)
This causes them to select Choice A (showing values 0, -4, -8)
The Bottom Line:
This problem tests careful attention to both the negative coefficient and the positive constant term. Success requires methodical substitution and accurate arithmetic with signed numbers.
| x | y |
|---|---|
| 0 | 0 |
| 1 | -4 |
| 2 | -8 |
| x | y |
|---|---|
| 0 | 40 |
| 1 | 44 |
| 2 | 48 |
| x | y |
|---|---|
| 0 | 40 |
| 1 | 36 |
| 2 | 32 |
| x | y |
|---|---|
| 0 | 0 |
| 1 | 4 |
| 2 | 8 |