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y = 9x + 12 x + 7y = 20 The solution to the given system of equations is \(\mathrm{(x,...

GMAT Algebra : (Alg) Questions

Source: Practice Test
Algebra
Systems of 2 linear equations in 2 variables
MEDIUM
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Notes
Post a Query

\(\mathrm{y = 9x + 12}\)

\(\mathrm{x + 7y = 20}\)

The solution to the given system of equations is \(\mathrm{(x, y)}\). What is the value of \(\mathrm{y}\)?

Enter your answer here
Solution

1. TRANSLATE the problem information

  • Given system of equations:
    • \(\mathrm{y = 9x + 12}\)
    • \(\mathrm{x + 7y = 20}\)
  • Find: The value of y

2. INFER the solution strategy

  • Notice that the first equation already has y isolated
  • This makes substitution the most efficient method
  • Plan: Substitute the expression for y from equation 1 into equation 2

3. SIMPLIFY through substitution

  • Substitute \(\mathrm{y = 9x + 12}\) into \(\mathrm{x + 7y = 20}\):
    \(\mathrm{x + 7(9x + 12) = 20}\)
  • Distribute carefully:
    \(\mathrm{x + 63x + 84 = 20}\)
  • Combine like terms:
    \(\mathrm{64x + 84 = 20}\)
  • Solve for x:
    \(\mathrm{64x = -64}\), so \(\mathrm{x = -1}\)

4. SIMPLIFY to find the final answer

  • Substitute \(\mathrm{x = -1}\) back into \(\mathrm{y = 9x + 12}\):
    \(\mathrm{y = 9(-1) + 12}\)
    \(\mathrm{= -9 + 12}\)
    \(\mathrm{= 3}\)

Answer: 3


Why Students Usually Falter on This Problem

Most Common Error Path:

Poor SIMPLIFY execution: Students make arithmetic errors when distributing \(\mathrm{7(9x + 12)}\), often getting \(\mathrm{7(9x) + 12 = 63x + 12}\) instead of \(\mathrm{63x + 84}\).

This leads to the wrong equation \(\mathrm{64x + 12 = 20}\), giving \(\mathrm{x = 1/8}\), and then \(\mathrm{y = 9(1/8) + 12 = 105/8 \approx 13.125}\). This leads to confusion and guessing since such decimal values rarely appear in answer choices.

Second Most Common Error:

Incomplete solution process: Students solve for x correctly but forget to substitute back to find y, stopping at \(\mathrm{x = -1}\).

Since the question asks specifically for the value of y, this causes them to get stuck and randomly select an answer.

The Bottom Line:

While identifying substitution as the strategy is straightforward, success requires careful arithmetic execution through multiple algebraic steps, especially during distribution and when substituting negative values.

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