y = 9x + 12 x + 7y = 20 The solution to the given system of equations is \(\mathrm{(x,...
GMAT Algebra : (Alg) Questions
\(\mathrm{y = 9x + 12}\)
\(\mathrm{x + 7y = 20}\)
The solution to the given system of equations is \(\mathrm{(x, y)}\). What is the value of \(\mathrm{y}\)?
1. TRANSLATE the problem information
- Given system of equations:
- \(\mathrm{y = 9x + 12}\)
- \(\mathrm{x + 7y = 20}\)
- Find: The value of y
2. INFER the solution strategy
- Notice that the first equation already has y isolated
- This makes substitution the most efficient method
- Plan: Substitute the expression for y from equation 1 into equation 2
3. SIMPLIFY through substitution
- Substitute \(\mathrm{y = 9x + 12}\) into \(\mathrm{x + 7y = 20}\):
\(\mathrm{x + 7(9x + 12) = 20}\) - Distribute carefully:
\(\mathrm{x + 63x + 84 = 20}\) - Combine like terms:
\(\mathrm{64x + 84 = 20}\) - Solve for x:
\(\mathrm{64x = -64}\), so \(\mathrm{x = -1}\)
4. SIMPLIFY to find the final answer
- Substitute \(\mathrm{x = -1}\) back into \(\mathrm{y = 9x + 12}\):
\(\mathrm{y = 9(-1) + 12}\)
\(\mathrm{= -9 + 12}\)
\(\mathrm{= 3}\)
Answer: 3
Why Students Usually Falter on This Problem
Most Common Error Path:
Poor SIMPLIFY execution: Students make arithmetic errors when distributing \(\mathrm{7(9x + 12)}\), often getting \(\mathrm{7(9x) + 12 = 63x + 12}\) instead of \(\mathrm{63x + 84}\).
This leads to the wrong equation \(\mathrm{64x + 12 = 20}\), giving \(\mathrm{x = 1/8}\), and then \(\mathrm{y = 9(1/8) + 12 = 105/8 \approx 13.125}\). This leads to confusion and guessing since such decimal values rarely appear in answer choices.
Second Most Common Error:
Incomplete solution process: Students solve for x correctly but forget to substitute back to find y, stopping at \(\mathrm{x = -1}\).
Since the question asks specifically for the value of y, this causes them to get stuck and randomly select an answer.
The Bottom Line:
While identifying substitution as the strategy is straightforward, success requires careful arithmetic execution through multiple algebraic steps, especially during distribution and when substituting negative values.